the channel capacity (information in bits per second) is related to bandwidth and SNR by the relation
C= B[log(1+SNR) b/s
log is at the base 2
B= bandwidth of a channel
C= capacity in bits per second
SNR= signal to noise ratio.
The roll-off factor of a digital filter defines how much more bandwidth the filter occupies than that of an ideal "brick-wall" filter, whose bandwidth is the theoretical minimum Nyquist bandwidth. The Nyquist bandwidth is simply the symbol rate expressed in Hz: Nyquist Bandwidth (Hz) = Symbol Rate (Sym/s) However, a real-world filter will require more bandwidth, and the excess over the Nyquist bandwidth is expressed by the roll-off factor. Suppose a filter has a Nyquist bandwidth of 100 MHz but actually occupies 120 MHz; in this case its roll-off factor is 0.2, i.e. the excess bandwidth is 0.2 times the Nyquist bandwidth and the total filter pass-bandwidth is 1.2 times the Nyquist bandwidth.
For NRZ we require large bandwidth,because transition will not occur in middle of bit.whereas in Manhaster encoding transition will occur middle of the bit so Data rate = Modulation rate/2 Regards, Dilip Prajapati
everyone, As far as I know the Full power bandwidth is the output bandwidth of the signal when it is made to obtain the max power from output suppose max output voltage is +/- 10 V as prescribed in the data sheet and the slew rate is 600V/u sec , then the full power bandwidth will be 600/(2*pi*10) that is 9.548 MHz
"W" for watts, or wattage
Return to ZeroA type of digital signal where 1's and 0's are pulses of opposite polarity, but between each bit the line returns to the zero (ground) state. It is rather inefficient in terms of bandwidth/data rate, as each bit transmitted uses two baud (i.e. state changes).
The roll-off factor of a digital filter defines how much more bandwidth the filter occupies than that of an ideal "brick-wall" filter, whose bandwidth is the theoretical minimum Nyquist bandwidth. The Nyquist bandwidth is simply the symbol rate expressed in Hz: Nyquist Bandwidth (Hz) = Symbol Rate (Sym/s) However, a real-world filter will require more bandwidth, and the excess over the Nyquist bandwidth is expressed by the roll-off factor. Suppose a filter has a Nyquist bandwidth of 100 MHz but actually occupies 120 MHz; in this case its roll-off factor is 0.2, i.e. the excess bandwidth is 0.2 times the Nyquist bandwidth and the total filter pass-bandwidth is 1.2 times the Nyquist bandwidth.
According to Shannon's Channel Capacity Equation: R = W*log2(1 + C/N) = W*log2(1+ SNR) Where, R = Maximum Data rate (symbol rate) W = Bw = Nyquist Bandwidth = samples/sec = 1/Ts C = Carrier Power N = Total Noise Power SNR = Signal to Noise Ratio
http://ieeexplore.ieee.org/Xplore/login.jsp?url=/iel5/35/14678/00667424.pdf?temp=x
Bandwidth:- It is one characteristics that measures network performance is bandwidth. Bandwidth can be measured in two values:- 1. IN HERTZ 2. IN BITS/SEC. Bit Rate:- It is used to describes digital signals. the bit rate is the no of bits sent in 1s
Bandwidth is the measure of range or band of frequencies that a channel or path can handle at a maximum rate. whereas, throughput is the average rate of successful message delivery over a communication channel. and Goodput is simply the changing in throughput rate.
There is relationship between pulse rate and hemoglobin count because as per your blood sensitivity you got your pulse rate high and low so this is true that there is relation ship between pulse rate and hemoglobin count.
The data rate (C) is equal to the bandwidth (B) times the logarithm base 2 of 1 plus the signal-to-noise ratio (S/N) (how much interference is introduced in the transmission of data)C = B x log2(1 + S/N)So your data rate is directly proportional to your bandwidth. If you increase your bandwidth, your data rate will also increase provided the signal-to-noise ratio isn't affected.
Frequency is a measure of the number of occurrences of a repeating event per unit time. The bandwidth of a frequncy is simply the difference between the upper and lower frequencies.
We can use the law B=(1+d)*S where B is the bandwidth S is the signal rate d is between 0 and 1 (depend on modulation and filtering) Thanks
Bandwidth of an optical fiber determines the data rate.
thhe rate is eating ice crem and the breathing rate is eating chocolate ice cream
I dont no sir