It is not the number of bulbs that you worry about. It is the wire size that is your concern. If the circuit is wired with AWG 12/2 wire then use a 20 amp breaker. If it is wired with a AWG 14/2 wire then use a 15 amp breaker. You are protecting the wiring with the correct size breaker.
A breaker is sized by the wire size. The wire is sized by the amperage. The formula for amperage is I = W/E. Amps = Watts/Volts. As you can see with no voltage stated an answer can not be given.
The breaker protects the wiring not the boiler. 12,000 watts at 240 volts will require 50 amps. So, you will need a 60 amp breaker using AWG# 6 wire on a dedicated circuit.
The question isn't the number of amps total on your branch circuits, but rather, what your MAIN breaker(s) are rated at. This will determine what size of generator you will need. And be certain that the generator is 3-phase. <<>> The formula you are looking for is Amps = kva x 1000/1.73 x voltage.
The use of a breaker in a circuit is to protect the wire size used in the circuit from becoming overloaded. Using the wattage of the load does not help for breaker sizing because the breaker operates on amperage. Amperage can be found from wattage by using the following equation. I = W /E. Amps = Watts / Volts. As you can see the amperage can not be calculated because there is no voltage stated.
3000 / 240 = Amps. You de-rate a breaker by 20 % for continuous load like an oven. You could get by with a 20 Amp breaker and 12 AWG wire. However, I would recommend 30 Amps and 10 AWG for an oven for the long run.
To calculate the breaker size for a 1500-watt 120-volt heater, use the formula: Breaker size = Power (Watts) / Volts. In this case, 1500 watts / 120 volts = 12.5 amps. Therefore, you would need a 15-amp breaker for a 1500-watt 120-volt heater to allow for a safety margin.
A breaker is sized by the wire size. The wire is sized by the amperage. The formula for amperage is I = W/E. Amps = Watts/Volts. As you can see with no voltage stated an answer can not be given.
The sizing of a breaker is dependant upon the size of the wire it protects. The size of the wire is dependant upon what the load current in amps is. Without the amperage and wattage and the voltage of the appliances an answer can not be given. W = A x V, Amps = Watts/ Volts.
The breaker protects the wiring not the boiler. 12,000 watts at 240 volts will require 50 amps. So, you will need a 60 amp breaker using AWG# 6 wire on a dedicated circuit.
50amp but if considering the breaker cannot withstand starting current you need to size the breaker up.
For a 2500 watt water heater operating at 120 volts, you would need a 20 amp breaker. This ensures the breaker can handle the load without tripping.
For a 30 amp breaker, you will need a wire that is at least 10 gauge in size.
To determine the appropriate breaker size for a 6000-watt oven operating at 240 volts, you first calculate the amperage using the formula: Amps = Watts / Volts. This gives you 6000 watts ÷ 240 volts = 25 amps. According to the National Electrical Code (NEC), it's advisable to use a breaker rated at 125% of the continuous load, so a 30-amp breaker would be appropriate for this oven.
Ovens typically run at 240 volts which will be a two pole breaker in your panel. Watts = volts x amps. 4800 / 240 = 20 amps. If by chance you are using 120 volts then double it to 40 amps. All wiring must conform to size of breaker used.
For a 13.8 kW electric heater at 208 volts, you would need a 3-phase circuit with a minimum of a 50-amp breaker to handle the load safely. This calculation is done by dividing the power (13,800 watts) by the voltage (208 volts) and then dividing by the square root of 3 (since it's a 3-phase system).
For a 50 amp breaker, you will need a wire that is at least 6 gauge in size to safely handle the electrical load.
If it is a portable generator the breaker should be self contained within the generators panel. If the generator is a stationary standby unit a voltage has to be stated to calculate the conductor size and hence the breaker size to protect the conductor. Amps = Watts/Volts.