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To determine the voltage required to pass 0.5 A of current through a 4.5-W bulb, you can use the formula P = V * I, where P is power, V is voltage, and I is current. Given that power is 4.5 W and current is 0.5 A, you can rearrange the formula to solve for voltage: V = P / I. Plugging in the values, V = 4.5 W / 0.5 A, which equals 9 volts. Therefore, 9 volts is required to pass 0.5 A of current through a 4.5-W bulb.
What else can I help you with?
What is the current through each light bulb in a series circuit?
it remains same i=voltage/total resistance
Is the current always the same in parallel circuits?
An example of a parallel circuit would be the light bulbs in track lighting. Each bulb has the same voltage applied. The current through any one light bulb equals the voltage divided by the resistance of the bulb. The current also equals the wattage of the bulb divided by the voltage. So if all the bulbs had exactly the same resistance the current would be the same. However, your question says "always" so in general the answer is no. In the case of track lighting if you had a 60 watt bulb in parallel with a 120 watt bulb, the 60W bulb would draw 1/2 amp and the 120W bulb would draw 1 amp. The sum of the current flowing in a parallel circuit equals the sum of the current in each leg of the circuit.
Why is there zero current when a light bulb burns out?
there is no voltage and resistance
Would you show me a diagram of a series circuit?
Diagrams are not supported with WikiAnswers, sorry, so you will have to use your imagination...A simple series circuit can be built with a battery, a switch, and a light bulb. One end of the battery is connected to one end of the switch. The other end of the switch is connected to one end of the bulb. The other end of the bulb is connected to the other end of the battery.If the switch is open, no current flows, and the bulb does not illuminate. If the switch is closed, current flows, and the bulb illuminates. By Ohm's law, the current through the bulb is proportional to the battery voltage and inversely proportional to the resistance of the bulb. Note, of course, that we are talking about hot resistance of the bulb, because cold resistance is an entirely different thing, due to the temperature coefficient of the bulb. Also, by Kirchoff's current law, the current at every point in this simple series circuit is the same and, by Kirchoff's voltage law, the voltage across the battery is the same as the voltage across the bulb.
Why we called zero bulb to zero volt bulb?
the zero bulb required less amount of electricty to glow the voltage of bulb is below 5 volt
Watt is the current allowed to flow through a bulb?
The current flowing through a bulb is equal to the (voltage across the bulb) divided by the (bulb resistance), and can be expressed in Amperes. The rate at which the bulb dissipates energy is equal to (voltage across the bulb) times (current through the bulb), and can be expressed in watts.
What voltage is required to sustain a current of 0.50 through a light bulb resistance of 190?
The voltage of a circuit with a resistance of 250 ohms and a current of 0.95 amps is 237.5 volts. Ohms's law: Voltage = Current times Resistance
What can be inferred about the current passing through the bulb?
The current passing through the bulb is directly related to the voltage applied across it and the resistance of the bulb. Using Ohm's Law (I = V/R), we can calculate the current flowing through the bulb by knowing the voltage and resistance values. Additionally, the brightness of the bulb can also be an indicator of the current passing through it, as higher current typically results in a brighter bulb.
What voltage is required a pass 0.5 A of current through a 4.5-W bulb?
9 volts====================The question is a bit convoluted.The power dissipated by the bulb and the current through itboth depend on the voltage applied across it.In the real world, the way to ask this question would have to be:If a light bulb dissipates 4.5 W of power when 0.5 A of currentpasses through it, what voltage has been applied across it ?(And, for extra credit, what is the bulb's effective resistance ?)
Why can't a bulb turn on without electricity?
An incadescent bulb lights up because the voltage source creates a current through the filament of the bulb and it heats up because of its composition and gives off light as a result. No electricity, no voltage and no current.
How much current flows in a 75-walt's light-bulb connected to a 110 voltage wall outlet?
The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
What is the current through each light bulb in a series circuit?
it remains same i=voltage/total resistance
Will the current in a light bulb connected to a 200-v source be greater or less than when the same bulb is connected to a 110-v circuit?
The current in the light bulb will be greater when connected to the 200-v source compared to the 110-v circuit, assuming the resistance of the light bulb remains constant. This is because current is directly proportional to voltage in an electrical circuit according to Ohm's Law (I = V/R), so a higher voltage will result in a greater current flow through the bulb.
How do you calculate the power rating of a bulb?
The power rating of a bulb is calculated by multiplying the voltage across the bulb by the current passing through it. The formula is P = V * I, where P is power in watts, V is voltage in volts, and I is current in amperes. This calculation helps determine the amount of energy the bulb consumes during operation.
What happens when one bulb is added to a series circuit?
The resistance is increased, the voltage across each bulb is decreased and the current through the circuit is reduced.
How do you work out the current of a light bulb?
You can use Ohm's Law to calculate the current of a light bulb by dividing the voltage across the light bulb by its resistance, which is typically provided on the bulb itself or its packaging. The formula is: Current (I) = Voltage (V) / Resistance (R).
What voltage is required to run a 75 watt light bulb if the current is 0.5 Amps?
For a resistive load like an incandescent light bulb Watts = Volts * Amps. In your home your voltage is fixed and may fluctuate somewhat due to a number of factors. The math is easy for a 60W bulb at 120 volts which yields a current of 1/2 (.5) Amps. The current for 75 W bulb at 120 V would be .625 A. You would need a 150VAC source to only draw .5 A.
