The current flowing through the 75-watt light bulb connected to a 110-volt wall outlet can be calculated by using the formula: Power = Voltage x Current. Therefore, the current flowing through the light bulb would be approximately 0.68 amps.
A transformer must be connected to an alternating current (AC) supply of the correct voltage.
To determine the current drawn by a watt lamp when connected to a voltage ( V ), you can use the formula ( I = \frac{P}{V} ), where ( I ) is the current in amperes, ( P ) is the power in watts, and ( V ) is the voltage in volts. For example, a 60-watt lamp connected to a 120-volt supply would draw ( I = \frac{60}{120} = 0.5 ) amperes.
No, a transformer changes the ac to a voltage that the user requires. After that a rectifier can be connected to it to provide dc.
Voltage can be found using Ohm's Law, which states that voltage (V) is equal to the current (I) flowing through a circuit multiplied by the resistance (R) of the circuit: V = I x R. It can also be measured directly using a voltmeter connected across the components of interest in the circuit.
Find out your supply voltage, and divide 65 by it: I(amps) = P(watts)/V(volts) = 65/V
because there is no voltage and resistance?
To find the current in a lightbulb using the equation ( V = IR ), you can rearrange it to ( I = \frac{V}{R} ). If the voltage ( V ) is 10.0 V, you would need the resistance ( R ) value to calculate the current ( I ). Once you have the resistance, simply divide 10.0 V by that resistance to find the current in amps.
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Balanced Star (Wye) Connected Systems:Line Voltage = 1.732 x Phase VoltageLine Current = Phase CurrentBalanced Delta Connected Systems:Line Voltage = Phase VoltageLine Current = 1.732 x Phase Current
The current, if connected to a voltage source that can supply the needed current to (R1+R2) R3, will be unchanged. If the source cannot supply the needed current, the terminal voltage will decrease, which will change the current flowing through R1 and R2.
The higher the resistance the dimmer the light will become. The voltage drop (current) is proportional to the resistance as seen in the equation V=IR, since voltage remains the same throughout a series circuit if the equivalent resistance goes up the amount of current reaching the lightbulb must go down to equal the voltage thus creating a dimmer lightbulb.
If two ideal sources of unequal voltage are connected in parallel the higher voltage will provide a majority of the current (a two percent difference in voltage would provide an additional 5% of the current) and (in the case of batteries) the larger would provide charging current, quickly draining it.
Here it is the current sampler and it is connected in series. while the voltage mixer connected in series.
V = irv = (0.5)(250)v = 125
for reducing the leakage current.
Measure the current and voltage on the secondary side.
a voltage source has very less(negligible)resistance.thus is considered as a short.if connected in parallel to a resistor will draw all the current acting as a short.thus is always connected in series of a resistor.where as a current source has tremendous resistance(infinity).thus if connected in series will be conidered as an open branch and no current will flow through it other than the source current.