To find the voltage required to send a current of 4 amps through a resistance of 60 ohms, you can use Ohm's Law:
V = I x R
where V is the voltage, I is the current, and R is the resistance.
Plugging in the values:
V = 4 amps x 60 ohms
V = 240 volts
So, you would need 240 volts to send 4 amps through a 60-ohm resistor.
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
voltage and resistance v=ir v=voltage i=current r=resistance in physics right now
U = RxI so 11x20=220 volts
Resistance affects how much current can flow; a higher resistance means either less current, or more voltage required for the same current. They are related in formula by V = IR, i.e. the product of resistance and current is the voltage across that component. Knowing any two allows you to work out the third. ANSWER REMOVING IMPIRICAL MAGNETUDES IT IS SIMPLY A RATIO 1:1:1
The three electrical quantities are current voltage and resistance. Current is measured in amperes (A) and is the rate at which electricity flows through a conductor. Voltage is measured in volts (V) and is the electrical force pushing the current through the conductor. Resistance is measured in ohms () and is the opposition to the flow of current. Current - measured in amperes (A) Voltage - measured in volts (V) Resistance - measured in ohms ()
The voltage of a circuit with a resistance of 250 ohms and a current of 0.95 amps is 237.5 volts. Ohms's law: Voltage = Current times Resistance
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
To find the voltage required to move 2 amps through a resistance of 5 ohms, you can use Ohm's Law, which states that voltage (V) equals current (I) multiplied by resistance (R). Therefore, V = I × R = 2 amps × 5 ohms = 10 volts. So, a voltage of 10 volts is required.
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
-- Connect a source of known, small voltage across the ends of the unknown resistance. -- Measure the resulting current through the unknown resistance. -- Divide (small known voltage)/(measured current). The quotient is the formerly unknown resistance.
Volts = Current x Resistance. The voltage is where the potential resides for the amount of current flowing through a resistance. Think about the voltage as a potential source of electrons that then flow through a circuit depending on the Load, or resistance in this example.
In a d.c. circuit, voltage drop is the product of resistance and current through that resistance.
Ohm's Law states that the relationship between resistance, current, and voltage is given by the equation V IR, where V is the voltage, I is the current, and R is the resistance. This means that for a given voltage, the current flowing through a circuit is inversely proportional to the resistance - as resistance increases, current decreases, and vice versa.
In an electrical circuit, the relationship between voltage and resistance is described by Ohm's Law. This law states that the voltage across a circuit is directly proportional to the resistance in the circuit. In other words, as resistance increases, the voltage required to maintain the same current also increases. Conversely, if resistance decreases, the voltage required to maintain the same current decreases.
The current flowing through the heating coil will depend on the resistance of the coil and the voltage of the power source. Using Ohm's Law (I = V/R), where I is the current, V is the voltage, and R is the resistance, you can calculate the current. The higher the voltage or lower the resistance, the higher the current.