The resistance can be derived from:
P = V^2/R
R = V^2/P
For the 100w bulb:
R = 220^2/100 = 484 ohms
For the 25w bulb:
R = 220^2/25 = 1936 ohms
When connected in series, and then connected to 440V, the voltage across the 100w bulb would be:
V = 440*484/(484+1936) = 88V
This is well within spec.
The voltage across the 25w bulb would be:
V = 440*1936/(484+1936) = 352v
This is way over spec, and would cause the bulb to fuse.
Although this answer assumes that a light bulb is a linear resistor, they are not. The resistance of a light bulb changes significantly with voltage and filiament temperature. The 25w light bulb is still the one that fuses, but the non-linearity of the resistance needs to be understood.
All residential loads are connected in parallel, so that they share the same supply voltage, which is necessary for them to develop their rated power outputs.
For an electrical load, such as a lamp, heater or motor, to operate at its rated power, it must be subject to its rated voltage which always corresponds to the supply voltage. For this to happen, individual loads must be connected in parallel with the supply and with each other. So all the electrical loads in your home, in your car, etc., are ALL connected in parallel.
To get full brightness, the rated voltage has to be applied across the bulb. When several bulbs are connected in series, the voltage gets devided among these sevral bulbs and correct rated voltage will not be applied acros each bulb, hence the brightness reduces.
Batteries in series makes the voltage additive. If the bulb is only rated at a specific voltage and you double the voltage the bulb will glow brighter but its life span will be shortened. Batteries in parallel will keep the voltage at the same level as a single battery but the endurance drain of the batteries will be doubled. Example, if a battery is drained of power, with a bulb being left on continuously, in one hour then two batteries in parallel would allow the bulb to glow for two hours before the batteries were drained of power.
Ups can be connected to an inverter since it does not exceed the rated voltage
All residential loads are connected in parallel, so that they share the same supply voltage, which is necessary for them to develop their rated power outputs.
It depends on the voltage rating of each lamp, and the value of the supply voltage. It's important to understand that a lamp will only operate at its rated power (therefore at its full brightness) when subject to its rated voltage.So, let's assume each lamp is rated at, say, 24 V.If connected in parallel across a 24-V supply, then they will both operate of full brightness.If connected in series across the same 24-V supply, then each lamp will be subject to half its rated voltage, and will be very dim.On the other hand, if connected in series across a 48-V supply, then they will each be subject to 24 V, and will both operate at full brightness.
For a lamp to operate at its rated power, it must be subjected to its rated voltage. Provided this is the case, then it doesn't matter whether lamps are connected in series or in parallel. For example, ten identical lamps, each rated at 12 V, will operate normally if connected in series across a 120-V supply (this is because they will each be subjected to a voltage drop of 12 V). They will also function normally if they are connected in parallel across a 12-V supply.
Power supply units are rated based on their output and efficiency. When more equipment is connected, a higher output power supply is needed.
Lamps connected in parallel are subject to the same voltage. Provided this voltage corresponds to the lamps' rated voltage, then each lamp will operate at its rated power and at its full rated brightness.Individual lamps connected in series operate below their rated voltage (the sum of the voltage drops around a series circuit equals the supply voltage) and will, therefore, operate below their rated power and brightness. The lamps will vary in brightness; those with the lower power ratings will be brightest and those with the higher power ratings will be least bright.
Circuits in all buildings are connected in parallel so that the loads connected in each 'branch' are all subject to the same (supply) voltage, enabling them to operate at their rated powers. A secondary advantage is that, with a parallel circuit, if one branch fails, then all the other branches will continue to operate normally.
It depends on the voltage rating of each lamp, and the value of the supply voltage. It's important to understand that a lamp will only operate at its rated power (therefore at its full brightness) when subject to its rated voltage.So, let's assume each lamp is rated at, say, 24 V.If connected in parallel across a 24-V supply, then they will both operate of full brightness.If connected in series across the same 24-V supply, then each lamp will be subject to half its rated voltage, and will be very dim.On the other hand, if connected in series across a 48-V supply, then they will each be subject to 24 V, and will both operate at full brightness.
For any appliance or lamp to operate at its rated power, it must be subjected to its rated voltage. Every branch of a parallel circuit is subjected to the same (supply) voltage. This is the main reason; the secondary reason is that any break in a series circuit will de-energise all the appliances connected to it!
To operate at its rated power, a lamp must be subject to its rated voltage (the supply voltage). As each branch of a parallel circuit is subject to the same voltage (the supply voltage), each lamp will operate at its rated power.
For an electrical load, such as a lamp, heater or motor, to operate at its rated power, it must be subject to its rated voltage which always corresponds to the supply voltage. For this to happen, individual loads must be connected in parallel with the supply and with each other. So all the electrical loads in your home, in your car, etc., are ALL connected in parallel.
When two light bulbs are connected in series , there is voltage drop which causes the second lamp to dimAnswerWhen two lamps are connected in series, neither lamp will be subject to its rated voltage and, so, each lamp will be dim. Surprisingly, perhaps, the lamp with the higher power will be dimmer than the lamp with the lower power!
The rated powers, printed on each lamp, will no longer apply. You will need to measure the load current (I) drawn by the two lamps, together with the supply voltage (U), and multiply the two values together: Power = U I