Because the angle of the power phasor is the difference between the one of voltaje and the one of current. As they are multiplied,instead of being added they are substracted
current that does't use in power measurement is called reactive current.
A short circuit = 0 ohm, from this one can use ohms law to calculate the current, that is E/R voltage divided by resistance as in this instance your resistance is zero and you can't divide by zero so your current will be infinit. In other words if your power supply is large enough to supply 200 amp, your current on a short circuit will be 200 amp.
Click the link. There you can figure the size generator you need.
S = Apparent Power P = Real Power [Negative for supplied power, positive for absorbed power] Q = Reactive Power [Positive for lagging or inductive loads, negative for leading or capactive loads] Fp = Power Factor [Specified as lagging or leading for inductive or capacitive loads respectively] V = Voltage I = Current * = (Conjugate) < = 'At an angle of' For DC cases: |P| = P = V x I = V^2 / R = I^2 x R For AC cases: S = V x I* = |S| < arccos(Fp) |S| = |V| x |I| |P| = |S| x Fp |Q| = sqrt(|S|^2 - |P|^2)
Phase angle is defined as the angle by which the load current leads or lags the supply voltage in an AC circuit. There are numerous ways to calculate a circuit's phase angle, so there is no 'formula' as such. For example, if you know a load's resistance and impedance, or its true power and apparent power, then you can use basic trigonometry to calculate the phase angle, and so on.
current=watts(power)/voltage
Not enough information. Power = current x voltage. Since voltage can be anything, there is no way to calculate power. Time is irrelevant; though once you have the power, it can help you calculate energy (energy = power x time).
Power = voltage x current Number of power in volts
Since power is the product of voltage and current, you will need to find out the power rating of the headlamp when on low beam. To find the current, divide the power of the lamp by the voltage (12 V).
If you are talking electrical power, take a sample as an array of double of the current, same for voltage, use the RMS block on both I, V and multiply the result.
use a calculator!
That depends, based on what information you want to calculate it.
Use Ohm's law: V = IR (V=voltage, I=current, R=resistance). Example: 3mA flows thru a 1kOhm resistor. V = (0.003 * 1000) = 3V.
to fine I (current) when you have R (resistance) and V (voltage) you use the formula: I = V / R
All you can do is get in the ballpark knowing resistance of windings and the supply voltage. Current = Voltage divided by resistance. Wattage = voltage x current x power factor. For a motor the power factor is between zero and sone number less than one, with one being just a resistive load. So if you calculate the current and use a PF = 1 you can get worse case wattage.
A short circuit = 0 ohm, from this one can use ohms law to calculate the current, that is E/R voltage divided by resistance as in this instance your resistance is zero and you can't divide by zero so your current will be infinit. In other words if your power supply is large enough to supply 200 amp, your current on a short circuit will be 200 amp.
current that does't use in power measurement is called reactive current.