There may be an "open neutral" somewhere either in your breaker panel or in the meter base.
Contact a qualified electrician to help solve the problem. An open neutral causes one leg of the electrical service to be "low" voltage, while the other leg goes "high". That can result in premature failure of electrical components, such as light bulbs, electronic devices and electric motors.
Output from secondary is about 6.8V rms, on no load. On the primary side, you have 140 / 120 = .86 volts per turn. Therefore, on the secondary side you will have 8*.86 = 6.8 volts.
86
If a cable insulation is described as RHW, you would be able to use the cable for what maximum temperature? A. 194°FB. 140°FC. 86°FD. 167°F
Tesla died penniless at age 86 on January 7, 1943. In his lifetime, he received over 800 different patents. Scientists continue to scour through his notes.
The ideal temperature for an electrical panel should generally be between 20°C to 30°C (68°F to 86°F). However, temperatures should not exceed 50°C (122°F) to prevent overheating and potential damage to electrical components. Regular monitoring and maintenance are essential to ensure that the panel operates within safe temperature limits.
86% of 120 is 103.2
There are 1 times 86 in 120. The answer you divide 120 by 86 which would get you 1.3953488372093. The remainder is 34 Similar Questions With Same Answer = 1.3953488372093.
Output from secondary is about 6.8V rms, on no load. On the primary side, you have 140 / 120 = .86 volts per turn. Therefore, on the secondary side you will have 8*.86 = 6.8 volts.
Output from secondary is about 6.8V rms, on no load. On the primary side, you have 140 / 120 = .86 volts per turn. Therefore, on the secondary side you will have 8*.86 = 6.8 volts.
71.67%
8 + 6 = 14 and 40 + 80 = 120. So therefore 48 + 86 = 14 + 120 which is 134
39.5349% increase.
72% is usually a C minus.
7 + 21 + 2 + 86 + 4 = 120
86 students, 34 teachers pop: 120
You can power an 86 volt light with a power source that outputs 86 volts, such as a specific battery or power supply designed for that voltage. Ensure that the power source can provide enough current to safely operate the light without damaging it.
Depending on the type, about 250 calories.