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you use 20log for voltages and 10log for power
10log(vo^2/vi^2) = 2*10log(vo/vi) = 20log(vo/vi)
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What is meant by the term large signal amplifier?
power amplifiers are the amplifier which raise the power levels of the signal.the power amplifier may also defined as a device which converts dc power to ac power and whose action is controlled by the ac input signal. Power amplifiers are also known as "LARGE SIGNAL AMPLIFIER".the term large signal arises because they use large part of load line for their operation,but the small signal amplifiers are use only 10% load line for their operation.
A receiver requires 10nW as input power if all the system losses add up to 50dB then how much power is required from the source?
here, the power required by the receiver is the output power and that required from the source is input power. Gain in dB=10 log(output power/input power) we have, loss in dB = -gain in dB = 10 log(input power/output power) or, 50 = 10 log(input power/10nW) or, anti-log(5) = input power/10 nW so the power required from the source is antilog(5)*10nW = 1 mW
Can you hook two linear amps together to achieve great power than from the original transmitter?
Yes. Two or more linear amplifiers can be connected in series. The impedances must matched between them, and also the undistorted output power available from from the first amplifier must not exceed the input power required by the second amplifier to deliver its maximum undistorted output power, and so on. An example arrangement might look like this: 1 watt transmitter -> 10 watt amplifier -> 100 watt amplifier -> 1000 watt amplifier Amplifiers can be connected in parallel under certain conditions. The amplifiers must be identical in gain, phase, and amplitude performance. They should be identical in all respects for best success. A combiner or hybrid circuit is used to split the incoming signal equally between the amplifiers, and a (larger) hybrid circuit is used to combine the outputs of the amplifiers into one comon signal. YOU MAY ADD another more powerfull amplifier on the output in series to the original amplifier. What you realy want is a parallel amplifier to doubble your power.
Calculate the power out put of an amplifier that has an input of 15wand a gain of 25dB?
If you want to work in watts, convert 25dB to a scalling factor: 3dB = 2 x input 10dB = 10 x input 20dB = 100 x input ...25dB = 10 ^ (25/10) = 316.2 x input So the output is 15 Watts x 316.2 = 4.7kW If you want to work in dB, then convert 15 watts to dB: 10 * log |P| = dB = 10*log |15| = 11.76dB so the output is 11.76 + 25 = 36.76dB
If the input power is 375 milliwatts and the output power is 1.79 watts What would be the dB gain of this amplifier circuit?
If you're doing anything with amplifier circuits, you really need to understand dB and be able to calculate it on your own. Here is everything you need to know about dB: The definition. Please memorize this: dB gain = 10 log [ (final power) divided by (original power) ] In your example: Original power = 375 mW = 0.375 W Final power = 1.79 W (final) / (original) = ( 1.79 / 0.375 ) = 4.7733 log ( 4.7733 ) = 0.678 Gain = 10 times the log = 6.78 dB
What is the exact solution of 10 to the x power equals 97?
Take logs of both sides - you can use any base, to give the answer: 10^x = 97 → log(10^x) = log(97) → x log(10) = log(97) → x = log(97) ÷ log(10) If you use common logs (logs to base 10) - highly recommended in this case), then: lg(10) = 1 → x = lg(97)
How do you find logarithms using a calculator?
If you are using a scientific calculator you will have a key labelled "log". To find the logarithm (to base 10) of a number, simply enter "log" followed by the number that you want to log. If you want a natural logarithm - log to the base e - use the "ln" key instead. If you haven't got a scientific calculator, use the one on your computer.
What is the approximate solution of 10 to the x power subtract 4 equals 7 Can you explain how to get the answer please?
When the unknown is in the power you need to use logs (to any base) and the rule: log(a^b) = b × log(a) Thus: 10^x - 4 = 7 → 10^x = 11 → x log 10 = log 11 → x = log 11 ÷ log 10 If you use common logs (to base 10) then: lg 10 = 1 → x = lg 11 ≈ 1.04
How do you answer log 8 plus log 3 the base is assumed to be 10?
log base 10 of 24. Use your calculator. log(24)Thanks, but i mean after you get to log 10 of 24 it looks like this24=10^x how do I figure this i meanType in the "log(" button, then 24 if you're using a graphing calculator.Type in 24 then "log" if you're using a small scientific calculator.Spreadsheet programs can do it as well. Type this:=log(24)in a cell and press the Enter key.
The base 10 logarithm is called the logarithm and is often written as log x instead of log10 x?
Common
How would you solve 250 to the x power equals 400000?
250x = 400000 then x log 250 = log 400000 so x = log 400000 / log 250 Natural logs could have been used instead of logs to base 10.
How do you use the anti log on a TI-89 calculator'?
To find anti log of a number enter the number as the exponent of 10.
What is the log of 125?
What 'logarithm base are you using. If Base '10' per calculator The log(10)125 = 2.09691 However, You can use logs to any base So if we use base '5' Then log(5)125 = 3 Because 125 = 5^3
How do you add decibels?
The decibel is the common measure of sound intensity You can either use logarithmic calculators to add together two decibel values or you can ... ? 10 log (10x inverse log dBvalue/10 + 10x inverse log dBvalue/10) =
What is log 100 base e?
log 100 base e = log 100 base 10 / log e base 10 log 100 base 10 = 10g 10^2 base 10 = 2 log 10 base 10 = 2 log e base 10 = 0.434294 (calculator) log 100 base e = 2/0.434294 = 4.605175
What does log in algebra mean?
The log or logarithm is the power to which ten needs to be raised to equal a number. Log 10=1 because 10^1=10 Log 100=2 because 10^2=100 Sometimes we use different bases. Like base 2. Then it is what 2 is raised by to get the number. Log "base 2" 8=3 because 2^3=8
If y equals 10 then what is then what is y equals log x?
y = 10 y = log x (the base of the log is 10, common logarithm) 10 = log x so that, 10^10 = x 10,000,000,000 = x
