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The voltage drop is equal to the total resistance across which it is dropped multiplied by the current flowing through this resistance.

i.e. V=IR (where V is the voltage drop, I is the current and R is the resistance)

Thus, I=V/R

So I=5/1000 A = 5*10-3 A = 5 mA

So the current flowing through your circuit is 5mA. Note that this answer is theoretical, and that it may differ from what you observe in practice due to component tolerances (resistors with the gold band at the end are only accurate to within 10%).

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15y ago

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