Doubling the voltage in a circuit does not double the propagation speed in that circuit. It only doubles the available energy (volts is joules per coulomb), which doubles the current (amperes is coulombs per second), and quadruples the power (watts is joules per second).
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.
If resistance is halved while voltage remains constant, the current will double.
In a resistive load circuit, the power = multiplication of voltage and Current. By increasing the voltage power will not be increased. Power is defined by the load as per its design. If the voltage is higher the load current will reduce. However running a load at double the rated voltage is not good for the device. Insulation may fail.
no voltage will be induced on the secondary side of the motor as the windings will become saturated.
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.
Since current = voltage / resistance, I = V/R, the current in a circuit will double if either the voltage doubles, or the resistance is halved.
The voltage depends on how the two batteries are connected to one another. If they are connected in a series circuit (positive end to negative end) the voltage will double. If they are wired in a parallel circuit, (It
If you double the voltage in a circuit, the power is quadrupled, assuming the resistance stays the same.
the voltage and current doubles
If resistance is halved while voltage remains constant, the current will double.
In a very simple way. As long as nothing changes in the circuit, the current that flows from the power supply or battery into the circuit is directly proportional to the voltage of the supply. -- If you double the voltage across the ends of the circuit, the current will double. -- If you turn the voltage up to 3.4027 times its original value, the current will increase to 3.4027 times its original value. -- If you decrease the voltage by 81.7 percent, the current will decrease by 81.7 percent.
If the voltage in a circuit were doubled, the current would also double according to Ohm's Law (I = V/R), assuming the resistance in the circuit remains constant. This is because current is directly proportional to voltage when resistance is held constant.
In an electrical circuit, if resistance is doubled, EMF (measured in volts) stays constant, and current is halved.
If you double the the RC circuit input frequence, the magnitude of voltage and current depends on whether or not the RC circuit is configured low-pass or high-pass, and on whether or not the original frquency is close to the knee frequency (the -3db point). The question has insufficient information to be answered completely.
In a resistive load circuit, the power = multiplication of voltage and Current. By increasing the voltage power will not be increased. Power is defined by the load as per its design. If the voltage is higher the load current will reduce. However running a load at double the rated voltage is not good for the device. Insulation may fail.
no voltage will be induced on the secondary side of the motor as the windings will become saturated.
No, the amperage does not necessarily double when both the current and voltage are doubled. Amperage (current) is determined by Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). If both voltage and current are doubled while resistance remains constant, the new current would actually be four times the original current, not just double.