A five digit no is entered through the keyboard write a program to obtain the reversed no and to determine whether the original no and reversed no is equal or not?

Answer 1

1) first you have to find the reverse of an integer..

code is given below,

#include<stdio.h>

void main()

{

int a,b,m,s=0;

printf("enter the value of a");

scanf("%d",&a);

b=a;

while(a!= 0)

{

m=a%10;

s=s*10+m;

a=a/10;

}

if(s == b)

{

printf("original number is equal to the reversed number");

}

else

{

printf("original number is not equal to the reversed number");

Answer 2

#include
#include

using std::cin;
using std::cout;
using std::endl;
using std::string;

int main()
{
const int numberOfDig = 5;
string num = "0";
cout << endl << "Enter a five digit number: ";
cin >> num;

string revNum = "00000";
for (int i = 0; i < numberOfDig; i++)
{
revNum[numberOfDig - i - 1] = num[i];
}

cout << endl << "You have entered: " << num
<< endl << "Reversed number is: " << revNum
<< endl;

system("PAUSE");
return 0;
}

Answer 3

#include <stdio.h>

#include <conio.h>

{

unsigned long reverse(int);

int n;

clrscr();

Printf("reverse of a given no is:%lu",reverse(n));

getch();

}

unsigned long rev(int x);

{

unsigned long r=0;

while(x>0)

{

r=r*10+(x/10);

x=x/10;

}

return r;

}