The voltage drop should not exceed 3% on a feeder or branch circuit.
How do you calculate voltage drop for starting motor current
No, three phase motor overloads just monitor the motor's lines for an overload. Once detected the circuit holding the magnetic starter in will drop out and take the motor off line.
The voltage drop across the series field winding of a motor can be calculated using Ohm's Law (V = I × R), where V is the voltage drop, I is the current, and R is the resistance of the winding. If the resistance of the series field winding is known, you can multiply it by the current of 3 A to find the resultant voltage drop. Without the specific resistance value, the exact voltage drop cannot be determined.
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
it depends on what type of load. Motor amperage will drop off as voltage rises. loads such as lights will increase amperage with voltage rise.
voltage drop is be a problem.
How do you calculate voltage drop for starting motor current
It depends on the voltage that the motor needs, because a higher voltage requires less current for a given amount of power. Also a higher voltage can tolerate a higher voltage drop. So there are two things that lead to a thinner wire when the voltage is higher.
When doing voltage drop calculations the voltage to the connected devices should not drop below 3 % of the supplied voltage. <<>> "Most" appliances? that a tough one there is no standard. A few percent is no trouble, different appliances have different tolerances: no generalizations are possible.
NEC recommends a maximum 3% drop for branch circuits. 5 volts is well within this range. So, yes 5v drop is normally fine, unless the motor manufacturer has a more stringent requirement.
its lose
vikas tyagi
.24
No, three phase motor overloads just monitor the motor's lines for an overload. Once detected the circuit holding the magnetic starter in will drop out and take the motor off line.
The voltage drop across the series field winding of a motor can be calculated using Ohm's Law (V = I × R), where V is the voltage drop, I is the current, and R is the resistance of the winding. If the resistance of the series field winding is known, you can multiply it by the current of 3 A to find the resultant voltage drop. Without the specific resistance value, the exact voltage drop cannot be determined.
If the load current descrease, there is less voltage drop caused by the resistance of the wire, so the voltage is higher.
A voltage drop of 0.4 volts in a 12-volt system represents a drop of about 3.3%, which is generally considered acceptable for many applications. However, the acceptability can vary based on the specific requirements of the devices being powered and the length of the wiring. For critical applications or longer wire runs, aiming for a lower voltage drop is advisable to ensure optimal performance and efficiency.