5000 / 0.96 = 5,209 (rounded)
Yes, 51,000 ohms (or 51 kΩ) is a standard value for a 5% tolerance resistor. Resistors are often available in E12 and E24 series, where the E12 series includes values like 10k, 22k, 47k, and 100k, with 51k being a standard increment in the E24 series. Therefore, it is commonly used in electronic circuits where a specific resistance is required within that tolerance range.
I believe Thomas Edison said Genius is 10 percent inspiration and 90 percent perspiration.
100 percent means full voltage or 0 dB.When 75 percent of the voltage is lost you still have 25 percent of the voltage.25 percent means damped to (-)12 dB.
Generally, no; most electronic devices only consume between 5% and 20% of their normal operating power when in standby. Some devices like copiers or laser printers only consume a couple of percent of their normal power because printers consume a LOT of energy in normal use to fuse the toner to the paper.
in the mid-1990s about 55 percent of cement shipments in the United States was consumed in building construction, with 22 percent used for residential and 19 percent for commercial construction
Make 5,209 of them.
You would say the latter. eigh percent of microchips ARE defective
0.0475
10%
Resistors made to a 20% tolerance do not have a color in the 4th tolerance band.
10 percent of students go out instead of use electronic devices
.05*.95*.95=0.045125=4.5125%
.0504
Cystic fibrosis (CF) is an autosomal recessive genetic disorder, meaning that a child must inherit two copies of the defective CFTR gene—one from each parent—to develop the disease. When both parents are carriers of the CF gene mutation, there is a 25 percent chance with each pregnancy that their child will inherit both defective genes, resulting in cystic fibrosis. Additionally, there is a 50 percent chance the child will be a carrier (inheriting one defective gene) and a 25 percent chance the child will inherit two normal genes.
Homework question? This is actually not a question of probability: if 95% of the parts are non-defective, then 0.95 * 500 = 475 parts are non-defective. So there is zero (0) probability that fewer than 472 parts are non-defective. The question is different when any part has a probability (chance) of 95% of being non-defective. This is a so called Binomial distribution. Google knows the answer.
100*25/750= approximately 3.33%
electronic systems of a non-unified architecture type, accounting for 20.6 percent of shipment values; industrial multifunction process computers (5.8 percent); transmitters producing standardized electronic analog transmission signals (4.9 percent);