printf(\n "ENTER THE NUMBER\t");
scanf{"%d",&a);
while(a!=0);
{
r=a%2;
if(r==0)
printf("\n\n THE NUMBER IS EVEN \t");
else
printf("\n\n THE NUMBER IS ODD \t");
printf ("\n ENTER THE NUMBER \t");
scanf("%d",&a);
}
getch();
}
Public Sub Swap() dim inta as integer dim intb as integer dim intc as integer inta=4 intb=5 intb=inta intc=intb inta=intc End Sub
I assume you mean is an if the number is an integer multiple of 3i am unfamiliar with C but the theory would be,find if a is integer multiple of 3b=a/3b==round(b).if 1 "yes"else "no"this is an inefficiency way but will get the job done
Output a prompt.Either:Read from standard input (std::cin) to an integer.Or:Read a line from standard input (std::getline()) to a string.Create a string stream (std::stringstream) to read the string.Read from the string stream to an integer.For each integer from 2 to half the entered integer:If the entered integer is divisible by the current integer:The number is not prime.Exit the program.The number is prime.Exit the program.
its nice
hey..it s simple..make use of built-in function isdigit(character)..it s in stdlib.h...
Public Sub Swap() dim inta as integer dim intb as integer dim intc as integer inta=4 intb=5 intb=inta intc=intb inta=intc End Sub
Yes, of coarse it will, but it is unclear whether it will be virtual or a slide out keyboard.
That depends on what the categories are, and whether you're talking about a computer keyboard or a music keyboard. Percussion
Going through a program on paper to check whether it has errors.
No, -8.5 is not an integer. An integer is a number without any fractions.
Function isPrime(ByVal n As Integer) As Boolean If n < 2 Then Return False End If Dim sqrtn As Integer = Math.Sqrt(n) + 1 For i As Integer = 2 To sqrtn If (n Mod i) = 0 Then Return False End If Next Return True End Function
The specific arrangement of keys on a keyboard is a separate issue, from whether you are using physical keys or virtual keys. The virtual keyboard is an alternative to the actual keyboard, not to the QWERTY keyboard.
I assume you mean is an if the number is an integer multiple of 3i am unfamiliar with C but the theory would be,find if a is integer multiple of 3b=a/3b==round(b).if 1 "yes"else "no"this is an inefficiency way but will get the job done
The average price of a backlit keyboard is $50. This does depend however on the form factor (whether its for a PC or a tablet) and whether you want wireless connectivity or not.
Hi, 1) check for your keyboard whether it is an USB based keyboard, because after the OS loads all the drivers are going to start go that may be the problem. 2) check the keyboard itself whether it is working or not by view on the num lock light.
Output a prompt.Either:Read from standard input (std::cin) to an integer.Or:Read a line from standard input (std::getline()) to a string.Create a string stream (std::stringstream) to read the string.Read from the string stream to an integer.For each integer from 2 to half the entered integer:If the entered integer is divisible by the current integer:The number is not prime.Exit the program.The number is prime.Exit the program.
Do the addition, then convert to an integer. The result will depend on whether you want to round to the nearest integer, round up, or round down.