Biggest of three numbers using ternary operator in java?

Answer 1

// largest = largest of a, b, c

public class largest

{

public static void main(String args[])

{

int a,b,c,largest;

a=0;

b=0;

c=0;

a=Integer.parseInt(args[0]);

b=Integer.parseInt(args[1]);

c=Integer.parseInt(args[2]);

largest=a>b?(a>c?a:c):(b>c?b:c);

System.out.println("The largest no. of "+a+","+b+"and"+c+"is"+largest);

}

}

Answer 2

// Returns the largest value out of (a,b,c)

int getLargest(final int a, final int b, final int c) {

// Maximum of a and b

int ab = a>b?a:b;

// Maximum of ab and c
int max = ab>c?ab:c;

return max;

}

Answer 3

Initially assume the maximum is equal to the first number. Then compare the maximum to the second number; if the second number is larger than the temporary maximum, assign the second number to the maximum. Repeat for the third number.

If you use a for loop, and an array, you can easily expand the program to get the largest out of much larger sets of numbers.

Initially assume the maximum is equal to the first number. Then compare the maximum to the second number; if the second number is larger than the temporary maximum, assign the second number to the maximum. Repeat for the third number.

If you use a for loop, and an array, you can easily expand the program to get the largest out of much larger sets of numbers.

Initially assume the maximum is equal to the first number. Then compare the maximum to the second number; if the second number is larger than the temporary maximum, assign the second number to the maximum. Repeat for the third number.

If you use a for loop, and an array, you can easily expand the program to get the largest out of much larger sets of numbers.

Initially assume the maximum is equal to the first number. Then compare the maximum to the second number; if the second number is larger than the temporary maximum, assign the second number to the maximum. Repeat for the third number.

If you use a for loop, and an array, you can easily expand the program to get the largest out of much larger sets of numbers.

Answer 4

It seems quite complicated - and confusing - to try to do this using only the ternary operator. I suggest you use any method to sort the three numbers using an array (bubble sort should be appropriate, since there are only a few numbers), then take the second number. Note that this method can easily be extended to finding the largest, second-largest, third-largest, etc. number, from among a set of any size.

Answer 5

Initially assume the maximum is equal to the first number. Then compare the maximum to the second number; if the second number is larger than the temporary maximum, assign the second number to the maximum. Repeat for the third number.

If you use a for loop, and an array, you can easily expand the program to get the largest out of much larger sets of numbers.