The following program implements a user-defined class for rational numbers, including operator overloads for all arithmetic operations (+, -, * and /).
Note that the class does not handle 0/n fractions properly because the reciprocal of 0/n is n/0 which is an invalid fraction with undefined value. The problem is that 0/n fractions are perfectly valid (1/2 - 1/2 = 0/2) so you need to cater for them (they simplify to zero), but you cannot divide by them. It is left as an exercise for the reader to provide handlers to cater for this type of exception.
#include<iostream>
#include<string>
#include<sstream>
// GCF: greatest common factor (AKA: GCD, greatest common divisor)
int gcf (int a, int b)
{
// Recursive Euclid algorithm.
return (b != 0 ) ? gcf (b, a % b) : a;
}
// LCM: least common multiple
int lcm(int a, int b)
{
return (b / gcf (a, b)) * a;
}
// Class to store rational numbers (fractions).
class rational
{
friend std::ostream& operator<< (std::ostream&, const rational&);
private:
int m_p;
int m_q;
public:
rational (const int = 1, const int = 1);
rational (const rational&);
rational (const std::string& str);
rational (const char* c_str);
rational& operator= (const rational&);
rational& operator= (const std::string&);
rational& operator= (const char*);
rational& operator-= (const rational&);
rational& operator*= (const rational&);
rational& operator/= (const rational&);
rational& operator+= (const rational&);
rational operator- (const rational&);
rational operator* (const rational&);
rational operator/ (const rational&);
rational operator+ (const rational&);
rational reciprocal() const;
rational& simplify ();
rational& unsimplify (int multiple);
bool operator slash_pos)
{
std::string p = str.substr (0, slash_pos++);
std::string q = str.substr (slash_pos, str.size()-slash_pos);
std::stringstream ssp (p);
std::stringstream ssq (q);
int ip;
int iq;
if (ssp >> ip && ssq >> iq && iq != 0)
{
m_p = ip;
m_q = iq;
return *this;
}
}
}
return *this;
}
// Equality operator.
bool rational::operator== (const rational& other) const
{
// Simplify both fractions before comparing.
rational copy (*this);
rational temp (other);
copy.simplify();
temp.simplify();
return copy.m_p==temp.m_p && copy.m_q==temp.m_q;
}
// Return the reciprocal by value (swap numerator/denominator)
rational rational::reciprocal() const
{
return rational (m_q, m_p);
}
// Simplifies the fraction.
rational& rational::simplify()
{
// Simplify the sign.
if (m_q<0)
{
m_p *= -1;
m_q *= -1;
}
int factor = gcf (this->m_p, this->m_q);
this->m_p /= factor;
this->m_q /= factor;
return *this;
}
// Usimplifies the fraction (use given denominator)
rational& rational::unsimplify (int denominator)
{
this->m_p *= denominator / m_q;
this->m_q = denominator;
return *this;
}
// Test drive the rational class.
int main()
{
// Test arithmetic.
rational a = "1/2";
rational b (2, 5); // e.g., "2/5"
std::cout << a << " + " << b << " = " << a + b << std::endl;
std::cout << a << " - " << b << " = " << a - b << std::endl;
std::cout << a << " * " << b << " = " << a * b << std::endl;
std::cout << a << " / " << b << " = " << a / b << std::endl;
// Test simplifier on negatives and integers.
rational c (2, -5); // -2/5
rational d (-2, -5); // 2/5
rational e (3, -1); // -3
std::cout << c << " simplified is ";
std::cout << c.simplify() << std::endl;
std::cout << d << " simplified is ";
std::cout << d.simplify() << std::endl;
std::cout << e << " simplified is ";
std::cout << e.simplify() << std::endl;
}
How do you calculate Emerson class numbers
65 % or above and in hons its 75%
The C++ standard library provides a class complex in <complex>, including all the standard arithmetic operator overloads. It is highly unlikely that a user-defined implementation will improve upon any of the existing implementations, however the source code is worthy of study, particularly if you wish to extend the implementation in order to cater for a user-defined scalar; all the built-in scalars are already catered for.
Certainly not in a primitive data type. You can store it in a String, of course. Now, if you want do treat it as a number and do actual calculations, you can store such large numbers in an object based on the BigInteger class; this class allows you to work with numbers of an arbitrary size, limited only by available memory. (There is also a similar BigDecimal class that allows you to work with numbers with decimals).
A div tag in HTML represents a division, usually with its own style, class, or alignment. For example, the HTML <div align=center>Text</center> would align the text in the center of the page
Class we are going to learn division. Hope you learn your multiplication.
find the rational between1and3
Not at all. The class of "natural" numbers are all positive, but the classes of "real" numbers and "rational" numbers include negative numbers.
multiplication (or division) bingo your say a problem and if they have the correct answer they cover up a spot
the collection of rational and irrational numbeers is known as real numbers
Class 4 division 1 (more properly called Division 4.1) is for flammable solids.
There is no Class 3 Division 2; Class three has no subdivisions.
Math! More specifically, depending on the level, you might study basic operations (addition, subtraction, multiplication, division) with integers; basic operations with decimals; basic operations with fractions; basic operations with negative numbers; percentages; ratio and proportion; algebra; calculus; trigonometry; and many others more.
Because division of two numbers a and b is defined to return the fraction a/b, which is actually an equivalence class of pairs (n*a,n*b) for all nonzero n, such that x/1 is identified with x for all numbers x.
The question is not well-posed, in that the term "bigger" can be understood in different ways. If A is a subset of B, we can call B bigger than A. However, in set theory, the cardinality of a set is defined as the class of sets with the "same number" of elements: Two sets A and B have the same cardinality if there exists a bijection f:A->B. Theorem: If there is an injection i:A->B and an injection i:B->A, then there is a bijection f:A->B. Not proved here. The set of integers and the set of rational numbers can be mapped as follows. Since the natural numbers are a subset of the rational numbers by i:N->R: n-> n/1, we have half of the proof. Now, order the rational numbers as follows: - assign to each rational number p/q (p,q > 0) the point (p,q) in the plane. Next, consider that you can assign a natural number to each rational number by walking through them in diagonals: (1,1) -> 1; (2,1) -> 2; (1,2) -> 3; (3,1) ->4 ; (2,2) ->5; (1,3) -> 6; (4,1) -> 7; (3,2) -> 8, (2,3) -> 9; (1,4) -> 10, etc. (make a drawing). It is clear that in this way you can assign a unique natural number to EACH rational number. This means that you have an injection from the rational numbers to the natural numbers. Now you have two injections, from the natural numbers to the rational numbers and from the rational numbers to the natural numbers. By the theorem, there is a bijection, which means that the natural numbers and the rational numbers have the same cardinality. Neither of them is "bigger" than the other in this sense. The cardinality of these two sets is called Aleph-zero, and the sets are also called countable (because the elements can be counted with the natural numbers).
You must remember that complex numbers need two parts - a real and an imaginar part, so you have to define fields for these parts. You also need to define methods at least for the basic operations, such as addition, subtraction, multiplication and division. You may also want to define methods for more advanced operations, such as trigonometric functions and the exponential function and natural logarithm, all of which have special definitions in the case of complex numbers.
DOT Class 3 is for flammable liquids, but there is no subdivision of the class so there is no division 3 for this class.