double mean(int list[], int arraySize)
{
double result=0;
for(int i=0; i<arraySize; ++i )
result += list[i];
return(result/size);
}
Your question isn't a question, but here is the answer: double divide (int p, int q);
AnswerYes, it can. For instance, if your function returns double you can assign the function call to a variable of type double.AnswerNo, only the returned value, of course.
double calcAreaRect (double a, double b);
You write a function that evaluates the square root of its argument and returns the result to the caller.You can also use the run-time library functions in math.h ...double sqrt (double x);double pow (double x, (double) 0.5);
Either you can use the pre defined function "pow" in the <math.h> header file OR you can make a user defined function to do the same operation. 1.Using the pre defined function in <math.h> : The function is a of datatype double and accepts only values in double. So, prototype declaration is: double pow(double x,double y); Pass the values to the function and it'll return the value of xy. In the calling function it can be declared as: double power=pow(x,y); 2.USER DEFINED FUNCTION: double power(double x,int y); int main() { double x,result; int y; cout<<"\nEnter the base: "<<; cin>>x; cout<<"\nEnter the exponential power: "; cin>>y; result=power(x,y); cout<<"The result of x to the power y is: "<<result; return 0; } double power(double x,int y) { for(int i=0;i<=y;i++) { x*=x; } return x; }
#include using std::cin;using std::cout;using std::endl;double minimum(double myArray[], const intarraySize);double maximum(double myArray[], const intarraySize);int main(){const int arraySize = 10;double myArray[arraySize] = {0.0};cout
Your question isn't a question, but here is the answer: double divide (int p, int q);
AnswerYes, it can. For instance, if your function returns double you can assign the function call to a variable of type double.AnswerNo, only the returned value, of course.
double calcAreaRect (double a, double b);
Here is an example for type double:#include using std::cin;using std::cout;using std::endl;double maxFirst(const double data[], int index);double maxSecond(const double data[], int index, double maxNumber1);double sum(double max1, double max2);int main(){const int arraySize = 10;double myArray[arraySize] ={0.0};cout
The general form of the pow function is: double pow(double base, double exp); Which returns the value of baseexp This function may be overloaded to allow for different parameter and return types, but the basic function is the same.
#include using std::cin;using std::cout;using std::endl;double maxFirst(const double data[], intindex);double maxSecond(const double data[], intindex, double maxNumber1);double sum(double max1, double max2);int main(){double myArray[] = {1.0,4.6,32.1,9.7,41.2,41.3,343,23,566.02,345.8,675.5,654.4};int arraySize = (sizeof myArray)/(sizeof myArray[0]);cout
You write a function that evaluates the square root of its argument and returns the result to the caller.You can also use the run-time library functions in math.h ...double sqrt (double x);double pow (double x, (double) 0.5);
Use #include <math.h>, and then add to your code the function pow(x, y), which returns double and equals to x to power y (x and are both double).
To calculate a double integral using the trapz function in MATLAB, you can first create a grid of points for the two variables you are integrating over. Then, evaluate the function you are integrating at these points to create a matrix of function values. Finally, use the trapz function twice - once along one dimension and then along the other dimension - to compute the double integral.
Either you can use the pre defined function "pow" in the <math.h> header file OR you can make a user defined function to do the same operation. 1.Using the pre defined function in <math.h> : The function is a of datatype double and accepts only values in double. So, prototype declaration is: double pow(double x,double y); Pass the values to the function and it'll return the value of xy. In the calling function it can be declared as: double power=pow(x,y); 2.USER DEFINED FUNCTION: double power(double x,int y); int main() { double x,result; int y; cout<<"\nEnter the base: "<<; cin>>x; cout<<"\nEnter the exponential power: "; cin>>y; result=power(x,y); cout<<"The result of x to the power y is: "<<result; return 0; } double power(double x,int y) { for(int i=0;i<=y;i++) { x*=x; } return x; }
double celsius (double fahrenheit) { return (fahrenheit - 32.) * 5. / 9.; }