#include
#include
void main()
{ char str[50];
int i,count,countc;
printf("Enter a string : ");
gets(str);
count=0;
i=0;
while(str[i]!='\0′)
{ if(str[i]==' ')
count++;
i++;
}
printf("The total number of words are %d ",count+1);
}
Read more: http://programmingkid.com/count-number-of-words-in-a-string/#ixzz1aGIR1odb
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
char *ptr;
public int getStringLength(String val) { return val.length(); } There is an inbuilt functionality in strings that counts the number of alphabets in a string called length()
//C program to accept a string from user and //display its ascii value and //then display sum of all ascii value of strings #include<stdio.h> #include <string.h> int main() { char String[100]; int Sum,Index; Sum=0; //Sum is initially zero printf("Enter the string:\n"); gets(String); //Accept String from User for(Index=0;Index<strlen(String);Index++) { Sum+=(String[Index]); //Adds (the ASCII values of) the String characters. } printf("The sum is %d\n",Sum); //Printing it as %d gives the equivalent ASCII value. return 0; }
A String is treated as an object, meaning there is an object on the heap. Of course, the variable you define is a pointer to the object, and it is stored on the stack.A String is treated as an object, meaning there is an object on the heap. Of course, the variable you define is a pointer to the object, and it is stored on the stack.A String is treated as an object, meaning there is an object on the heap. Of course, the variable you define is a pointer to the object, and it is stored on the stack.A String is treated as an object, meaning there is an object on the heap. Of course, the variable you define is a pointer to the object, and it is stored on the stack.
// Inventory Pointer // Demonstrates returning a pointer #include <iostream> #include <string> #include <vector> using namespace std; //returns a pointer to a string element string * ptrToElement(vector<string>* const pVec, int i); int main() { vector<string> inventory; inventory.push_back( "sword"); inventory.push_back( "armor"); inventory.push_back( "shield"); //displays string object that the returned pointer points to cout << "Sending the objected pointed to by returned pointer:\n"; cout << *(ptrToElement(&inventory, 0)) << "\n\n"; //assigns one pointer to another - inexpensive assignment cout << "Assigning the returned pointer to another pointer.\n"; string* pStr = ptrToElement(&inventory, 1); cout << "Sending the object pointed to by new pointer to cout:\n"; cout << *pStr << "\n\n"; //copies a string object - expensive assignment cout << "Assigning object pointed by pointer to a string object.\n"; string str = *(ptrToElement(&inventory, 2)); cout << "Sending the new string object to cout:\n"; cout << str << "\n\n"; //altering the string object through a returned pointer cout << "Altering an object through a returned pointer.\n"; *pStr = "Healing Potion"; cout << "Sending the altered object to cout:\n"; cout << inventory[1] << endl; return 0; } string * ptrToElement(vector<string>* const pVec, int i) { //returns address of the string in position i of vector that pVec points to return &((*pVec)[i]); }
One way to do this is to convert the number to a String, then use the corresponding String method to find out the length of the String.
C forbids converting a string constant to 'char' because string constants are stored in read-only memory, and attempting to modify them through a 'char' pointer can lead to undefined behavior and potential program crashes.
We use a pointer to reference a string because a string is an array of characters where every element is a char (or a wchar_t if using UNICODE strings). Passing arrays by value would require the entire array to be copied, but passing a pointer variable to an array only copies the pointer, which is effectively the same as passing the array by reference. #include <iostream> int main() { char * psz = "hello"; // pointer to a null-terminated string. std::cout << psz; // pass the pointer (by value) to the insertion operator. return( 0 ); }
Read the characters one at a time, and write an "if" for each of the cases. In each case, if the condition is fulfilled, increment the corresponding counter variable.
char *ptr;
public int getStringLength(String val) { return val.length(); } There is an inbuilt functionality in strings that counts the number of alphabets in a string called length()
ISO C forbids converting a string constant to 'char' in C because string constants are read-only and attempting to modify them through a 'char' pointer can lead to undefined behavior and potential program crashes.
//C program to accept a string from user and //display its ascii value and //then display sum of all ascii value of strings #include<stdio.h> #include <string.h> int main() { char String[100]; int Sum,Index; Sum=0; //Sum is initially zero printf("Enter the string:\n"); gets(String); //Accept String from User for(Index=0;Index<strlen(String);Index++) { Sum+=(String[Index]); //Adds (the ASCII values of) the String characters. } printf("The sum is %d\n",Sum); //Printing it as %d gives the equivalent ASCII value. return 0; }
int main (int argc, char **argv):Hereargv is a pointer to a pointer (points to the first element of a pointer-array)argv[0] is a pointer (points to the first character of a string)argv[0][0] is a character
A String is treated as an object, meaning there is an object on the heap. Of course, the variable you define is a pointer to the object, and it is stored on the stack.A String is treated as an object, meaning there is an object on the heap. Of course, the variable you define is a pointer to the object, and it is stored on the stack.A String is treated as an object, meaning there is an object on the heap. Of course, the variable you define is a pointer to the object, and it is stored on the stack.A String is treated as an object, meaning there is an object on the heap. Of course, the variable you define is a pointer to the object, and it is stored on the stack.
Nothing.The C language only recognizes a few keywords, like "for" and "if". Most of what's in a C program ... that doesn't reference routines in the C program itself ... are library calls, and cputs() is one of those. What it does is write its argument (which should be a pointer to a character string) to the console... console put string.