C program to determine sum of squares of all even numbers between 10 to 1000?

Answer 1

main()

{

int i,sumo=0,sume=0,oddno,evenno;

for(i=1,oddno=1,evenno=2;i<=100;++i,oddno=oddno+2,evenno=evenno+2)

{

sumo=sumo + oddno;

sume=sume + evenno;

}

printf("Sum of odd nos = %d And Sum of even nos = %d,sumo,sume);

}

Answer 2

#include<stdio.h>int main () {

int sum = 0;

for (int odd=3; odd<100; odd+=2) {

printf ("%d\n", odd);

sum += odd;

}

printf ("\nSum = %d\n", sum);

return 0;

}

Answer 3

#include<stdio.h>

#include<conio.h>

void main()

{

clrscr();

int i,sum=0;

for(i=2;i<=100;i=i+2)

{

sum=sum+i;

}

printf("sum of even no.%d",sum);

getch();

}

Answer 4

long sum = 0;

long i;

for (i=12; i<1000; i+=2) sum += i*i;

/* using long in case your compiler assumes 16 bit ints */