/*** returns N!, assume N >= 0 ***/
int Factorial(int n) {
if (n <=1 ) /* 0! = 1! = 1 */ return 1;
/** you can place as many know values as you want, like 2!, 3!, etc **/
/** but, recursive call will do just fine, ... **/
return n * Factorial(n - 1); /** compute N * (N-1)! **/
}
double factorial(double N){double total = 1;while (N > 1){total *= N;N--;}return total; // We are returning the value in variable title total//return factorial;}int main(){double myNumber = 0;cout > myNumber;cout
<html> <script language="vbscript"> n=cint(inputbox("Enter a number")) dim f f=1 if n<0 then Msgbox "Invalid number" elseif n=0 or n=1 then MsgBox "The factorial of given number "&n&" is :"&f else for i=n to 2 step -1 f=f*i next MsgBox "The factorial of given number "&n&" is :"&f end if </script> </html>
write an algorithm to print the factorial of a given number and then draw the flowchart. This looks like someones homework, defiantly someone looking for the easy way. When it comes to programming, the more you do the better you get. Experience counts (making your own mistakes and learning from the mistake).
A recursive function is one that calls upon itself until a given result in the original call is met. Take a look at this example. Program Recursion; Uses crt; Var number:longint; Function Factorial(number:longint):longint; Begin if number > 0 then factorial:=number*factorial(number-1) else factorial:=1; End; Begin clrscr; readln(number); writeln(factorial(number)); readln; End. Note how the function factorial calls itself.
// returns n! int fact(final int n) { // keep track of factorial calculation in f // f starts at n, and we will multiply it by all integers less than n int f = n; // loop from n-1 down to 2 for(int i = (n - 1); i > 1; --i) { // increase our total product f *= i; } return f; }
kjhk
Factorials are the product of 1 and all the integers up to the given number. Simply put, 5 factorial or 5! = 5*4*3*2*1
/*program to find the factorial of a given number*/ #include<stdio.h> #include<conio.h> int fact(int); void main() { int n,c; printf("\n enter the number for which you want to find the factorial"); scanf("%d",&n); c=fact(n); printf("\n the factorial of the number %d is %d",n,fact); getch(); } int fact(int n) { int k; if(n==0) return(1); else k=n*fact(n-1); return(k); }
i need a pic of cuson
double factorial(double N){double total = 1;while (N > 1){total *= N;N--;}return total; // We are returning the value in variable title total//return factorial;}int main(){double myNumber = 0;cout > myNumber;cout
no answer....pls post
answer:32 programme to print factorial of a given number in c languages
The number of diagonals in an n-sided polygon is given by nC2 - n (where n is the number of sides of the polygon) or in the expanded form: factorial (n) _______________________ {factorial (2) * factorial (n-2)} substituting (n = 6) for a hexagon we get the number of diagonals as 9. Similarly, substituting (n=5) for a pentagon we get the number of diagonals as 5.
<html> <script language="vbscript"> n=cint(inputbox("Enter a number")) dim f f=1 if n<0 then Msgbox "Invalid number" elseif n=0 or n=1 then MsgBox "The factorial of given number "&n&" is :"&f else for i=n to 2 step -1 f=f*i next MsgBox "The factorial of given number "&n&" is :"&f end if </script> </html>
write an algorithm to print the factorial of a given number and then draw the flowchart. This looks like someones homework, defiantly someone looking for the easy way. When it comes to programming, the more you do the better you get. Experience counts (making your own mistakes and learning from the mistake).
Kat
factorial n is given by formula n! = n.(n-1)....1 int i; long x; x =1; for (i=n;i>1;i--) x = x*i ; will calculate factorial. I have put x as long to avoid integer overflow. checks for n is positive etc. to be added.