class Abc
{
public static void main(String[] args)
{
System.out.println("Hello World!");
}
}
write a c++ program to convert binary number to decimal number by using while statement
by this program you can find the factorial: #include<iostream> using namespace std; main() { int n,x,f=1; cin>> n; x=0; while(x<n) { x++; f= f*x; } cout<<"factorial is"<<f<<"\n"; system("pause"); return 0; }
A = 5do{statement;A = A + 1;} while (A < 10)
Function sum_odd_digits(ByVal number As Integer) As Integer Dim digit As Integer sum_odd_digits = 0 While number <> 0 digit = number Mod 10 If digit And 1 Then sum_odd_digits = sum_odd_digits + digit number = number / 10 End While End Function
A program can be looped in Python by wrapping the entire program in a for or while loop. If you wish to loop the program a finite amount of times, it can be done like so (x = the amount of times you want it to loop, this can be a number or variable storing a number): for i in range(0,x): [code] If you wish to loop the program infinitely, you can use a simple while loop: while True: [code]
write a c++ program to convert binary number to decimal number by using while statement
The following cases are all possible:- program without any for and while- program without for- program without while- program with both for and while
/*Java program to find out square root of a given number * without using any Built-In Functions */ public class SquareRootDemo2 { public static void main(String[] args) { //Number for which square root is to be found double number = -12; //This method finds out the square root findSquareRoot(number); } /*This method finds out the square root without using any built-in functions and displays it */ public static void findSquareRoot(double number) { boolean isPositiveNumber = true; double g1; //if the number given is a 0 if(number==0) { System.out.println("Square root of "+number+" = "+0); } //If the number given is a -ve number else if(number<0) { number=-number; isPositiveNumber = false; } //Proceeding to find out square root of the number double squareRoot = number/2; do { g1=squareRoot; squareRoot = (g1 + (number/g1))/2; } while((g1-squareRoot)!=0); //Displays square root in the case of a positive number if(isPositiveNumber) { System.out.println("Square roots of "+number+" are "); System.out.println("+"+squareRoot); System.out.println("-"+squareRoot); } //Displays square root in the case of a -ve number else { System.out.println("Square roots of -"+number+" are "); System.out.println("+"+squareRoot+" i"); System.out.println("-"+squareRoot+" i"); } } }
That is any number that is an integer, and the square of another integer. For example, 4 is the square of 2, while 9 is the square of 3.That is any number that is an integer, and the square of another integer. For example, 4 is the square of 2, while 9 is the square of 3.That is any number that is an integer, and the square of another integer. For example, 4 is the square of 2, while 9 is the square of 3.That is any number that is an integer, and the square of another integer. For example, 4 is the square of 2, while 9 is the square of 3.
//program to find the factorial value f any number using while loop #include<stdio.h> void main() { int i,n,fact=1; printf("Enter the number\n"); scanf("%d",&n); i=n; while (i>=1) { fact=fact*i; i--; } printf("The factorial value=%d",fact); } the above is a program for calculating tha factorial value of any number which is entered by the user
In the RAM
The program is here guys.......... //Finding whether the given number is perfect or not //Starts here #include<stdio.h> void main() { int i=1,temp=0,number; scanf("%d",&number); while(i<=number/2){ if(number%i==0) temp+=i; i++; } if(temp==number) printf("Its a perfect number"); else printf("Its not a perfect number"); } //ends here
eleporo
Not used
by this program you can find the factorial: #include<iostream> using namespace std; main() { int n,x,f=1; cin>> n; x=0; while(x<n) { x++; f= f*x; } cout<<"factorial is"<<f<<"\n"; system("pause"); return 0; }
To multiply a number by itself is commonly known as squaring the number. The product is known as the square of the number while the number now becomes the square root of the product.
A = 5do{statement;A = A + 1;} while (A < 10)