No. By Kirchoff's Current Law, components in series all see the same current.
you should specify: - circuit topology, I assume a series connection. - diode allows current flow? It depends how it's connected - diode forward voltage drop value if diode is in forward conduction, you have VR=10V - VDIODE and, thus, I = VR/R=(10-Vdiode)/1200.
To drop the unwanted voltage.
The anode side of a diode should be connected to the positive voltage supply to make it conduct current. When the anode is at a higher potential than the cathode, the diode becomes forward biased and allows current to flow through it. If the cathode is at the higher potential, the diode remains reverse biased and does not conduct.
The current will flow in one direction only. That direction is indicated by, usually, a ring around one end of the diode. The current will flow from the unmarked end to the marked end.
In a zener diode, the voltage across it remains relatively constant over a wide range of reverse current, as long as it is operating within its specified breakdown region. Therefore, when the current through a zener diode increases by a factor of 2, the voltage across the zener diode does not significantly increase; it typically remains close to its specified zener voltage. Thus, the voltage does not increase by a factor of 2.
If diode is connected in series then current will flow only in one direction. ie. Current flow occurs only when diode is forward biased. ANSWER: It depends are the diodes are connected in series if they are back to back no current will flow if connected in the forward conduction mode then they will conduct.
The leakage current of a (zener) diode is the current that leaks when a diode is connected in reverse biased.
The leakage current of a (zener) diode is the current that leaks when a diode is connected in reverse biased.
A resistance is connected in series with p-n junction of diodes to limit the number of electrons that flow across the junction.
you should specify: - circuit topology, I assume a series connection. - diode allows current flow? It depends how it's connected - diode forward voltage drop value if diode is in forward conduction, you have VR=10V - VDIODE and, thus, I = VR/R=(10-Vdiode)/1200.
A series resistor is necessary when a diode is forward-biased to limit the current flowing through the diode and prevent damage to the diode. Without a series resistor, the diode could draw excess current and overheat, potentially causing it to fail. The resistor helps control the current and protect the diode in the circuit.
In a series circuit, devices are connected in a single path so that the current flows through each device in sequence. If one device fails or is removed, the circuit will be broken, and no current will flow.
To drop the unwanted voltage.
The anode side of a diode should be connected to the positive voltage supply to make it conduct current. When the anode is at a higher potential than the cathode, the diode becomes forward biased and allows current to flow through it. If the cathode is at the higher potential, the diode remains reverse biased and does not conduct.
The current will flow in one direction only. That direction is indicated by, usually, a ring around one end of the diode. The current will flow from the unmarked end to the marked end.
18 V
In a zener diode, the voltage across it remains relatively constant over a wide range of reverse current, as long as it is operating within its specified breakdown region. Therefore, when the current through a zener diode increases by a factor of 2, the voltage across the zener diode does not significantly increase; it typically remains close to its specified zener voltage. Thus, the voltage does not increase by a factor of 2.