1. Yes, but only inside data-structures with the 'bit fields'.
2. There is header called inttypes.h which gives you the following types: int8_t, int16_t, int32_t, int64_t (and unsigned variants).
In computer programming, a variable can be (among other things) an integer or a long integer. An integer can be any whole number in the range of -32,768 to 32,767 A long integer can be any whole number in the range of -2,147,483,648 tp 2,147,483,647 I have never heard of an "integer" variable being called a "short integer" but it makes a kind of sense. Note: The size of integer types is platform-dependent, but usually: short: 16 bits int: 32 bits (16 in archaic systems: MSDOS OS Windows16) long: 32 bits (64 in unix64) long long: 64 bits
11 bits (which actually allows -1024 to 1023)
A bitfield is an integer value treated as a sequence of bits which can be toggled individually as flags.
The highest unsigned integer is 255; The highest signed integer is 127.
zero bits
What is the decimal equivalent of the largest binary integer that can be obtained with (a) 11 bits and (b) 25 bits?
In computer programming, a variable can be (among other things) an integer or a long integer. An integer can be any whole number in the range of -32,768 to 32,767 A long integer can be any whole number in the range of -2,147,483,648 tp 2,147,483,647 I have never heard of an "integer" variable being called a "short integer" but it makes a kind of sense. Note: The size of integer types is platform-dependent, but usually: short: 16 bits int: 32 bits (16 in archaic systems: MSDOS OS Windows16) long: 32 bits (64 in unix64) long long: 64 bits
Bits administrator
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
The number of bits in an integer is the number of times you can divide the integer by 2, truncating each result, before you reach zero.
The highest positive integer that can be stored in seven bits is 127. This is because seven bits can represent values from 0 to (2^7 - 1), which equals 127. In binary, 127 is represented as 1111111.
2x-1
2x -1
8 bits = 1byte 2 bytes = 1int dint (double integer) = 4bytes = 32bits
Normally a computer allocates a certain amount of memory space to store a number. This means that larger numbers are rounded and so not as accurate. By specifying that a number is a long integer, it is allocated twice the amount of storage space.For example, the largest integer that can be stored in 8-bits is 2^8 - 1 = 255.By doubling the storage to 16 bit, it becomes 65535.
256x4=1024 bits are stored.128x8=1024 ,yes this chip can be specified as 128 byte
The largest integer is 211 - 1 which is 2048 - 1 = 2047