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Normally, no electron energy states exist in the band gap, the gap between the valence band and conduction band in a semiconductor.
However, if we dope the semiconductor, i.e. add donor (n type) or acceptor (p type) atoms to it, we introduce new electron energy states in the band gap!
Take for example silicon, in which we introduce phosphorus, which is a group V element and thus a donor atom. This will introduce extra filled electron states just below the conduction band.
Now, this all happens at 0K, so no current can flow (this is logical as electrons don't move at this temperature, even with an electric field applied). But if we raise the temperature e.g. until room temperature at 300K, the electrons gain energy and can jump into the free energy states in the conduction band. These electrons in the conduction band can now conduct electricity.
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What is the Disadvantages of semiconductor to other materials?
what is a semiconductor able to do that other materials cabbot
How you generate power set using c program?
#include <iostream> void printSet(int array[],int size){ int i; for (i=1;i<=size;i++) std::cout << array[i] << " "; std::cout << std::endl; return; } void printPowerset (int n){ int stack[10],k; stack[0]=0; /* 0 is not considered as part of the set */ k = 0; while(1){ if (stack[k]<n){ stack[k+1] = stack[k] + 1; k++; } else{ stack[k-1]++; k--; } if (k==0) break; printSet(stack,k); } return; } int main(){ printPowerset(4); return 0; }
C program for optimal merge pattern?
#include<iostream.h> #include<conio.h> void main() { clrscr(); int i,k,a[10],c[10],n,l; cout<<"Enter the no. of elements\t"; cin>>n; cout<<"\nEnter the sorted elments for optimal merge pattern"; for(i=0;i<n;i++) { cout<<"\t"; cin>>a[i]; } i=0;k=0; c[k]=a[i]+a[i+1]; i=2; while(i<n) { k++; if((c[k-1]+a[i])<=(a[i]+a[i+1])) { c[k]=c[k-1]+a[i]; } else { c[k]=a[i]+a[i+1]; i=i+2; while(i<n) { k++; if((c[k-1]+a[i])<=(c[k-2]+a[i])) { c[k]=c[k-1]+a[i]; } else { c[k]=c[k-2]+a[i]; }i++; } }i++; } k++; c[k]=c[k-1]+c[k-2]; cout<<"\n\nThe optimal sum are as follows......\n\n"; for(k=0;k<n-1;k++) { cout<<c[k]<<"\t"; } l=0; for(k=0;k<n-1;k++) { l=l+c[k]; } cout<<"\n\n The external path length is ......"<<l; getch(); }
Implementation of LZW compression algorithm in C?
{ unsigned char **dict; int *dlength; unsigned char p[80], temp[80]; char c; int plength,i,j,k,diff,cd; plength=1; cd=256; p[0]=EOF; dict= (unsigned char *)malloc(99999); //Allocating memory for Dictionary if(dict == NULL) printf("Unable to allocate memory \n"); dlength=(int *)malloc(99999); for (i = 0; i < 99999; i++) { dict[i]=(unsigned char *)malloc(60); if(dict[i]==NULL) printf("Unable to allocate memory \n"); } for (i=0;i<256;i++) //loading dictionary with ASCII set { dict[i][0]=i; dlength[i]=1; } while ((c = fgetc(Fpt)) != EOF) { if(cd==256) p[0]=(unsigned char *)c; diff=0; for (i=0; i<cd; i++) { for (k=0; k<plength; k++) //checking to see if p+c in dict { if(dict[i][k]!=p[k]) diff=1; } } if (diff==0) { p[plength]=(unsigned char)c; plength++; } if (diff==1) { for (i=0; i<cd; i++) { for (k=0; k<plength; k++) { if(dict[i][k]!=p[k]) diff=1; } if (diff==0) j=i; } fputc(j, outfile); for (i=0; i<plength; i++) { dict[cd][i]= p[i]; } dict[cd][plength]=(unsigned char)c; cd++; p[0]=c; } } for (i=0; i<cd; i++) { for (k=0; k<plength; k++) { if(dict[i][k]!=p[k]) diff=1; } if (diff==0) j=i; } fputc(j, outfile); fclose(outfile); fclose(Fpt); } By Amit Setia
K j equals j but how is that?
K j equals j when K is 1 or j is 0.
Why the semiconductor behave like a insulator as a zero?
O K is absolute zero. At absolute zero, the electrons of the semi conductors are trapped and are immovable from their electron shell as they are in a low energy state. This makes the pure semiconductor an insulator. One must heat the semiconductor to give the electrons enough energy to move to free them from their electron shell, and thus conduct.
What is the Disadvantages of semiconductor to other materials?
what is a semiconductor able to do that other materials cabbot
Classification of semiconductor memory?
,;';l;k';.mm'kmlkmkll'''lkl;;
Give some Examples of direct and indirect band gap semiconductors?
direct band gap-semiconductor in which the bottom of the conduction band and the top of the valence band occur at the momentum k=0;in the case of d.b.s. energy released during band-to-band electron recombination with a hole is converted primarily into radiation (radiant recombination); wavelength of emitted radiation is determined by the energy gap of semiconductor; examples of d.b.s. GaAs, InP, ZnS, ZnSs, CdS, CdSe etc. indirect bandgap semiconductor --semiconductor in which bottom of the conduction band does not occur at effective momentum k=0, i.e. is shifted with respect to the top of the valence band which occurs at k=0; energy released during electron recombination with a hole is converted primarily into phonon; e.g. Si, Ge, GaP, GaAsp ,Ge etc, .
Why you can divide 0 by 3 but not 3 by 0?
3*0 = 0 Dividing both sides by 3 gives 0 = 0/3 and therefore 0/3 is defined and is equal to 0. However, there is no number, k, such that k*0 = 3 and so division by 0 is not defined. If there were such a number k, then you could divide both sides by k to give 0 = 3/k. But there is no such k.
What has the author K V Ravi written?
K. V. Ravi has written: 'Imperfections and impurities in semiconductor silicon' -- subject(s): Defects, Semiconductors, Silicon
What is k minus k?
k - k = 0
What is the answer to this problem k squared minus 5k?
The expression ( k^2 - 5k ) can be factored as ( k(k - 5) ). To find the values of ( k ) that satisfy the equation ( k^2 - 5k = 0 ), you can set each factor to zero: ( k = 0 ) or ( k - 5 = 0 ), which gives ( k = 5 ). Thus, the solutions are ( k = 0 ) and ( k = 5 ).
How do K conduct a kneeling search?
paa-tuhod that the answers
How do you write a C-program for matrix multiplication?
it would have a part in it like this: for (i=0; i<n; ++i) { . for (j=0; j<l; ++j) { . . sum= 0; . . for (k=0; k<m; ++k) { . . . sum += a[i][k] * b[k][j]; . . } . . c[i][j] = sum; . } }
Factor the expression 2 k squared minus k minus 4 equals 0?
2 k^2 - k - 4 = 0 2 (k^2 - (1/2)k - 2) = 0 2 ((k - 1/4)^2 - 1/16 - 2) = 0 2 ((k - 1/4)^2 - 33/16) = 0 2 (k - 1/4 - sqrt(33)/4)(k - 1/4 + sqrt(33)/4) = 0 32 (4k - 1 - sqrt(33))(4k - 1 + sqrt(33)) = 0
What is a C program for square of sum of alternative prime numbers?
#includeint main(){int count,i,j,k,n,*a,sum=0;printf("Enter the value of 'n':");scanf("%d",&n);a=malloc(n*sizeof(int));for(i=1;i
