Field replacement of a capacitor when you don't have the correct size available.
It is an acceptable temporary fix to go up one rating size (for example, from a 5 microfarad original up to a 7.5 microfarad replacement) so long as the voltage of the replacement capacitor is equal to or greater than the original and the current draw under load does not exceed the appliance's current rating as stated on its rating plate.
It is important to stress that a capacitor of the correct size should be installed as soon as possible because a larger capacitor will allow a higher current to flow. (Larger meaning not the outside dimensions physically but the capacity in microfarads.) Assuming the supply voltage, supply frequency and everything else in the circuit stays the same, it is safest to assume that the current will increase directly in proportion to the increase in the microfarad capacity. So adding 50% more microfarads would result in 50% more current. If there is a transformer or a motor in the circuit the extra current could damage its windings or even cause a fire!
So be careful! IF YOU ARE NOT ALREADY SURE YOU CAN DO THIS JOB
SAFELY AND COMPETENTLY
REFER THIS WORK TO QUALIFIED PROFESSIONALS.
If you do this work yourself, always turn off the power
at the breaker box/fuse panel BEFORE you attempt to do any work AND
always use an electrician's test meter having metal-tipped probes
(not a simple proximity voltage indicator)
to insure the circuit is, in fact, de-energized.
Yes you can do it. more voltage is good, a little more capacitance is good. Be sure to use a good quality capacitor. Note: on the old capacitor, it might be stated the temperature ratings such as 85 deg. C, 105 deg C, etc. Observe this as well. Higher is better.
No! This is a term for capacitance. A capacitor will store a voltage up to it's breakdown limit plus cause a voltage reaction to a following circuit.
Not a good idea, without knowing more about the circuit in which it's installed. Presumably, the 440v capacitor was selected because its max voltage rating (440v) is higher than the instantaneous voltage to be expected at that point in the circuit. By that criterion, the voltage at that point in the circuit may exceed 370 volts, and your proposed replacement component won't hold it.
A: It may tattoo your face when it blow up if the 25 volts is used where a 50 volts should be, you may substitute 47 mfd 500 volts for the 50volts cap and the 25 volts cap But you cannot substitute 15 volts for the 25 volts capacitor
100 WVDC means 100 working volts DC. That is the maximum operating voltage that the capacitor is certified to have across it. Exceeding that rating could puncture a hole in the dielectric, leading to catastrophic failure of the capacitor.
uF is a measurment in electronics called Microfarad. You will typically see uF on Capacitors for example 400Volt 150uf would be a capacitor rated at 400 volts and 150 microfarad.
Yes you can do it. more voltage is good, a little more capacitance is good. Be sure to use a good quality capacitor. Note: on the old capacitor, it might be stated the temperature ratings such as 85 deg. C, 105 deg C, etc. Observe this as well. Higher is better.
In most cases, yes. Unless you're in some high precision device, you're probably working with a 5-10% tolerance which would allow a 15-30 microfarad variance. Even a 1% tolerance would give you 3 microfarads. You can go with the same or higher voltage rating, just not lower.
No! This is a term for capacitance. A capacitor will store a voltage up to it's breakdown limit plus cause a voltage reaction to a following circuit.
1000 microfarads is its rated capacitance, while 35 volts is its rated voltage.
If the motor is rated at 370 v and the supply is 370 v, the capacitor needs to be rated at 370 or more volts, so a 440 v capacitor will be OK.
C=Q/V12 where Q/ V12 is the Charge per Potential Difference between the plates of the capacitor. If you solve for Q, you see that the charge is proportional to this potential difference. You are likely to surpass your load requirements by increasing the charge/discharge amplitude with the 35 volt cap. In other words, your cap will charge up to 35 volts and then discharge that 35 volts onto your load that was set at resonance to operate with 16 volts discharging. Any separation of circuits using this cap would probably fry something on one side or the other over time. Hope this helps.
Farad = Coloumb / Volt; solving for Coloumb, you get Coloumb = Farad x Volt. Just plug in the numbers - 1 microfarad is a millionth farad; 0.001 microfarad - if that is what you mean - is 0.000000001 Farad; wherease 1 KV = 1000 Volts.
9200 volts my 1000 uF capacitor only holds 10 volts
Not a good idea, without knowing more about the circuit in which it's installed. Presumably, the 440v capacitor was selected because its max voltage rating (440v) is higher than the instantaneous voltage to be expected at that point in the circuit. By that criterion, the voltage at that point in the circuit may exceed 370 volts, and your proposed replacement component won't hold it.
A: It may tattoo your face when it blow up if the 25 volts is used where a 50 volts should be, you may substitute 47 mfd 500 volts for the 50volts cap and the 25 volts cap But you cannot substitute 15 volts for the 25 volts capacitor
When the terminals of a capacitor are connected together, the capacitor will discharge, returning to a zero potential state. Capacitors resist voltage change, meaning that if the capacitor is in a circuit that has zero voltage potential, the capacitor will eventually achieve zero potential. If the capacitor is in a circuit that has a 5 volt potential, the capacitor will seek and attempt to maintain that 5 volt potential (provided that the capacitor is rated at 5 volts or more). In an AC circuit, the capacitor will tend to smooth out the sin wave of the current, resisting change in both directions. In a DC power supply circuit, a capacitor will tend to reduce the voltage "ripple", and if the circuit is designed properly, will provide a smooth DC voltage. Shorting the terminals of a capacitor is effectively what often happens in many circuits; it's not a problem.