You mean you have written a program, but you don't understand it? Well, how could I explain it without seeing it?
To write a C program that calculates the Fibonacci series up to a given number, you can use a loop to generate the series. Start by initializing the first two Fibonacci numbers (0 and 1) and then repeatedly compute the next number by adding the two preceding numbers until you reach or exceed the specified limit. Here’s a simple example: #include <stdio.h> int main() { int n, t1 = 0, t2 = 1, nextTerm; printf("Enter a positive integer: "); scanf("%d", &n); printf("Fibonacci Series: %d, %d", t1, t2); for (int i = 3; i <= n; ++i) { nextTerm = t1 + t2; printf(", %d", nextTerm); t1 = t2; t2 = nextTerm; } return 0; } This program prompts the user for a number and prints the Fibonacci series up to that number.
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }
class Fibonacci { public static void main(String args[]) { System.out.println("enter the number upto u want"); int number=Integer.parseInt(args[0]); int a=0,b=1,c=0; System.out.print(a+" "+b); for(int i=1;i<=number;i++) { c=a+b; System.out.print(c+" "); a=b; b=c; } } } the number are given to the run time where are print the series eg: 5 0 1 1 2 3 5 8 13................
Explain the following terms in the context of object oriented programming. Also explain how these concepts are implemented in C++ by giving an example program for each.
#include<stdio.h> int main(){ int a[10],i,n,m,c=0; printf("Enter the size of an array: "); scanf("%d",&n); printf("Enter the elements of the array: "); for(i=0;i<=n-1;i++){ scanf("%d",&a[i]); } printf("Enter the number to be search: "); scanf("%d",&m); for(i=0;i<=n-1;i++){ if(a[i]==m){ c=1; break; } } if(c==0) printf("The number is not in the list"); else printf("The number is found"); return 0; }
Exactly what do you mean by 'C program in Java'
i dn't know. haha
//to generate Fibonacci series upto a range of 200....(in C).... #include<stdio.h> main() { int a,b,c,i; a=0; b=1; printf("\n FIBONACCI SERIES .....\t"); i=1; while(i<=(200-2)) { c=a+b; printf("\t%d",c); a=b; b=c; i++; } }
Yes, this can be done. For example for Fibonacci series. You will find plenty of examples if you google for the types of series you need to be generated.
#include #include void main() { clrscr() int a=0,b=1,c,i,n; coutn cout
To write a C program that calculates the Fibonacci series up to a given number, you can use a loop to generate the series. Start by initializing the first two Fibonacci numbers (0 and 1) and then repeatedly compute the next number by adding the two preceding numbers until you reach or exceed the specified limit. Here’s a simple example: #include <stdio.h> int main() { int n, t1 = 0, t2 = 1, nextTerm; printf("Enter a positive integer: "); scanf("%d", &n); printf("Fibonacci Series: %d, %d", t1, t2); for (int i = 3; i <= n; ++i) { nextTerm = t1 + t2; printf(", %d", nextTerm); t1 = t2; t2 = nextTerm; } return 0; } This program prompts the user for a number and prints the Fibonacci series up to that number.
/*WAP to display Fibonacci series*/ #include<stdio.h> #include<conio.h> void main() { int i,a=0,b=1,c; scanf("%d",&n); printf("%d\n%d",a,b); for(i=0;i<n;i++) { c=a+b; a=b; b=c; printf("\n%d",c); } getch(); }
[ Fibonacci series___: ] #include<stdio.h> int main(void) { int n,i,c,a=0,b=1; printf("Enter Fibonacci series of nth term : "); scanf("%d",&n); printf("%d %d ",a,b); for(i=0;i<=(n-3);i++) { c=a+b; a=b; b=c; printf("%d ",c); } }
to print the Fibonacci series until 100 you can take the input in d to make it run for whatever value you want void main(){ int a,b,c,d; a=0; b=1; c=1; d=100; while(c<d) { printf("%d\n",c); c=a+b; a=b; b=c; } }
see the program
#include<stdio.h> #include<conio.h> void main() { printf("The first 20numbers of Fibonacci series are:"); int a=0, b=1, c, n=2; printf("%d \t, %d", &a, &b); while(n<20) { c=a+b; printf("\t %d", &c); a=b; b=c; n++; } getch(); }
#include #include void main(void) { int i,j,k,n; clrscr(); i=0; j=1; printf("%d %d ",i,j); for(n=0;n<=5;n++) { k=i+j; i=j; j=k; printf("%d ",k); } getch(); }