Derive an expression for efficiency of full and half wave rectifier?

Answer 1

The efficiency(n) of fullwave rectifier is defined as: n=DC output Power/AC input power But Power=V*I n=Vdc*Idc/Vrms*Irms But Vdc=2Vm/pi,Idc=2Im/pi ,Irms=Im/root(2),Vrms=Vm/root(2) (Im:Peak Curent) n=(4Vm*Im/pi^2)/(Vm*Im/2)=8/pi^2=0.812=81.2%. So efficiency of full wave rectifier is 81.2%

Answer 2

A half wave rectifier basically throws away the negative half of the waveform. Full wave basically flips the negative part of the waveform to positive. From that standpoint you could say that full wave is twice as efficient.

Answer 3

The ratio of d.c power output to the applied input a.c power is known as rectifier efficiency .

Answer 4

Efficiency = (Vdc2/Rl)/(Vrms2/Rl) = (Vm/л)2/(Vm/2)2 = 0.406

Where Vm is the maximum voltage

Answer 5

maa chuda bhosdi wale

Answer 6

40.6%

Answer 7

81.2%

Answer 8

100