No, the printf()
statement in C can generate multiple lines of output. You can include newline characters (\n
) within the string to create line breaks, allowing for formatted output across multiple lines. Additionally, you can call printf()
multiple times to print different lines.
The println method outputs a newline character after the arguments you pass to it. The code for println basically looks like: public void println(String x) { print(x); newLine(); }
#include <stdio.h> #include <conio.h> void main() { int height, line, i; clrscr(); scanf("%d", &height); for (i = 0; i < height - 1; ++i) printf(" "); printf("1\n"); for (line = 1; line < height; ++line) { for (i = 0; i < height - line - 1; ++i) printf(" "); for (i = 0; i < line; ++i) printf("%d", line + 1); printf(" "); for (i = 0; i < line; ++i) printf("%d", line + 1); printf("\n"); } getch(); }
#include<stdio.h> #include<conio.h> int main() { int i=0,opt; printf("Enter your choice\n"); printf("1. Horizontal line"); printf("\n2. Vertical line\n"); scanf("%d",&opt); if(opt==1) { for(i=0;i<=50;i++) printf("%c",196); } else { for(i=0;i<=40;i++) printf("%c\n",179); } return 0; }
Of course not.
Java doesn't have a printf method. To provide the implementation of printf method of C in java, the java has two print methods. They are1. print()2. println()The first method prints the text in braces on the same line, while the second is used to print on the next line. In fact, ln in println() stands for next line. We need not use /n while working in java.Actually, the System.out.format() function is practically identical to printf in C. When translating code from C to Java, you can generally replace all calls to printf(args...) with calls to System.out.format(args...)....and to answer the original question, Java's System.out.format() method is based off of C's printf() function.
When a loop encounters a break statement, code execution will immediately exit the loop and begin again at the next line after the loop. int i = 0; while(1) { i = i + 1; if(i == 3) { break; } printf("%d ", i); } printf("broken"); Output for the above block of code will be: "1 2 broken" Once i is increased to 3, the if statement holds true and code execution will move to the line outside of the loop block.
The println method outputs a newline character after the arguments you pass to it. The code for println basically looks like: public void println(String x) { print(x); newLine(); }
It can be done with dark magic or a double loop: num= 0; for (line=1; line<=7; ++line) { for (i=1; i<=line; ++i) { printf ("%d", ++num); } putchar ('\n'); }
#include<stdio.h> int main(){ int line,i,j,k; printf("Enter the no. of lines"); scanf("%d",&line); for(i=1;i<=line;i++){ for(j=1;j<=line-i;j++) printf(" "); for(k=1;k<i;k++) printf("%d",k); for(k=i;k>=1;k--) printf("%d",k); printf("\n"); } return 0; }
#include <stdio.h> #include <conio.h> void main() { int height, line, i; clrscr(); scanf("%d", &height); for (i = 0; i < height - 1; ++i) printf(" "); printf("1\n"); for (line = 1; line < height; ++line) { for (i = 0; i < height - line - 1; ++i) printf(" "); for (i = 0; i < line; ++i) printf("%d", line + 1); printf(" "); for (i = 0; i < line; ++i) printf("%d", line + 1); printf("\n"); } getch(); }
To print "thank you" in inverted commas in C programming, you can use the following code: #include <stdio.h> int main() { printf("\"thank you\"\n"); return 0; } This code will display the output as: "thank you"
#include<stdio.h> #include<conio.h> int main() { int i=0,opt; printf("Enter your choice\n"); printf("1. Horizontal line"); printf("\n2. Vertical line\n"); scanf("%d",&opt); if(opt==1) { for(i=0;i<=50;i++) printf("%c",196); } else { for(i=0;i<=40;i++) printf("%c\n",179); } return 0; }
Basic Program in "C" #include <stdio.h> /*This is the standard input/output library function*/ main(void) /*All C programs must have the function main*/ { char ch; printf("This is a C Program."); /* Every line of code in C must end with a semi colon*/ printf("Welcome to C!");/*the printf outputs the line of text to the screen*/ scanf("%c%c", &ch, &ch); /* This is a trick way to pause the computer so you can read the information on the screen*/ return 0; /* Indicates that your program has terminated successfully*/
Of course not.
No, it has a line leve output and a headphone output.
#include <stdio.h> #include <conio.h> int main() { int iWidth = 0, iHeight = 0, iLoop = 0, jLoop = 0; printf("\nEnter the width of Rectangle:"); scanf("%d",&iWidth); printf("\nEnter the height of Rectangle:"); scanf("%d",&iHeight); //To draw the first horizontal line for(iLoop = 0; iLoop < iWidth; iLoop++) printf("*"); printf("\n"); //Drawing the vertical lines for(iLoop = 0; iLoop < iHeight; iLoop++) { printf("*"); for(jLoop = 0; jLoop < iWidth-2; jLoop++) printf(" "); printf("*\n"); } //Last horizontal Line for(iLoop = 0; iLoop < iWidth; iLoop++) printf("*"); getche(); return 0; }
int main (void) { printf ("One line programme\n"); return 0; }