Not possible, because there is no such thing as 'biggest even number'
write an algorithm to print first N even numbers
design a flowchart that will input three numbers and get their sum. If the sum is greater than 20, then print "sum>20",else print the sum.
11
start input A & B if A>B print A is greatest if B>A print B is greatest stop james ola writes.....SOT.
Arrange the any one of the order and store the memory in order vice (ie.Ascending for Descending) Then print the second data of that array it is simple way
write an algorithm to print first N even numbers
#include(stdio.h) int main ()
design a flowchart that will input three numbers and get their sum. If the sum is greater than 20, then print "sum>20",else print the sum.
first sort the ten numbers in descending order and print the first number. That will be the largest no
11
Start Input A Input B C=A+B Print C END
start input A & B if A>B print A is greatest if B>A print B is greatest stop james ola writes.....SOT.
c the book mastering c
Arrange the any one of the order and store the memory in order vice (ie.Ascending for Descending) Then print the second data of that array it is simple way
According to www.BookLibris.com, the numbers on the title page, near the copyright, is the print history of the book. If you have a 1 on the end, it is a 1st edition/1st printing.
Hi
Input the numbers into an array, sort the numbers in descending order, then print the results. If there are fewer than, say, 20 numbers, then a bubble sort will suffice. Otherwise use a more advanced sorting algorithm such as quick sort.