Power is voltage times current. If power and voltage remains the same, then current cannot decrease - it must also remain the same.
The only viable explanation, assuming the question is valid, is that there is a parallel circuit, and one resistance increases while the other decreases, keeping the net resistance the same, but shifting the power from one branch to the other.
Another answer
Normally, if the voltage remains the same and the current decreases in a particular circuit, then the resistance of that circuit must be increasing and the total energy input must also reduce.
If the total energy input remains constant (and yet the voltage remains the same) then some of the current being supplied by the source - and therefore also some of the energy - must be going to some other place outside the circuit in question, e.g. there could now be a ground fault...
In a passive circuit, the current will decrease. In an active industrial circuit, it will usually decrease. In a theoretic manner - it is an unknown.
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
It is halved. coz voltage=current * resistance
If resistance is halved while voltage remains constant, the current will double.
Current will increase
the current will increase because of a lower level of resistance , hence more current will flow- easily
Current increases if the voltage remains constant.
In a passive circuit, the current will decrease. In an active industrial circuit, it will usually decrease. In a theoretic manner - it is an unknown.
If the current decreases while energy input and voltage remain constant, it means that there is an increase in resistance within the circuit. This could be due to factors such as a faulty component, a loose connection, or an increase in temperature affecting the resistance of the materials in the circuit.
The physical equation governing voltage is V = IR, where V is voltage, I is current, and R is resistance. If V remains constant while R is increased, I or current must decrease. Increasing the resistance in a circuit is simply introducing a material that further resists or impedes the electron flow (current), thus current decreases.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
It is halved. coz voltage=current * resistance
Yes. The current is inversely proportional to the resistance. I = V / R where I is current, V is voltage, and R is resistance. Adding light bulbs adds resistance. Current is constant throughout a series circuit; it doesn't change no matter what. Voltage changes.
Ohm's Law answers your question. Voltage = Current x Resistance. In a series circuit you are in effect adding resistance. If the Voltage remains constant then the answer is obvious looking at the equation above.
If resistance is halved while voltage remains constant, the current will double.