no difference is there. if you connect an uncharged one to a battery/voltage source,current flow will be there for a short time which will tend to charge or in more precise manner will develop charge on its plates.if you connect this charged one to a resister or some load,then capacitor will itself act as a voltage source sending current in the circuit at the expense of the charge present on it.this is discharging current.both are same bunt one tends to put up charge while other does the opposite.
The product of resistance and capacitance is referred to as the time constant. It determines rate of charging and discharging of a capacitor.
The voltage across a capacitors given as a time constant t= 63% the resistor value multiply buy capacitor value. it doesn't matter if it goes more or less negative it will follow this function
capacitor's characteristic is charging and discharging. discharged energy will be dropped by load . so it is connected in parallel
ac passes by repeatedly charging and discharging the capacitor. when you study ac circuit analysis, you will find out about impedance and reactance, which will allow you to compute how ac behaves in capacitors and inductors.
When a capacitor is discharging, current is flowing out of the capacitor to other elements in the circuit, similar to a battery. Current flowing out of an element, by convention, is defined as negative current, while current flowing into an element, such as a resistor, is defined as positive current. Thus a discharging capacitor will always have a negative current.
Explain how a discharging capacitor in an electronic divice produce complex waveform?
The product of resistance and capacitance is referred to as the time constant. It determines rate of charging and discharging of a capacitor.
If the resistance is in series with the capacitor, the charge/discharge time is extended.
Capacitor is nothing but a storage device. It has a dielectric media in between the two electrodes. the nature of the capacitor is charging and discharging the voltage.
In a circuit with a capacitor, resistance and capacitance are related in how they affect the charging and discharging process of the capacitor. Resistance limits the flow of current in the circuit, which affects how quickly the capacitor charges and discharges. Higher resistance slows down the charging and discharging process, while lower resistance speeds it up. Capacitance, on the other hand, determines how much charge the capacitor can store. Together, resistance and capacitance impact the overall behavior of the circuit with a capacitor.
In the experiment of flashing and quenching of a capacitor, the neon bulb twinkles because the charging and discharging of the capacitor cause the voltage across the capacitor to fluctuate rapidly. These fluctuations can cause the neon bulb to turn on and off, leading to the twinkling effect.
The relationship between capacitor resistance and the overall performance of an electronic circuit is that the resistance of a capacitor affects the charging and discharging times of the capacitor, which can impact the timing and stability of the circuit. Higher resistance can lead to slower charging and discharging, potentially affecting the circuit's functionality and efficiency.
No, the time constant is different for discharging and charging capacitors. The time constant for charging a capacitor is given by the product of the resistance and capacitance (τ = RC), while for discharging it is given by the product of the resistance and the remaining capacitance (τ = RC).
The charging time of a capacitor is usually lower than the discharging time because during charging, the voltage across the capacitor is increasing from zero to its maximum value, which initially allows a higher current to flow. During discharging, the voltage across the capacitor is decreasing from its maximum value to zero, resulting in a lower current flow. This difference in current flow affects the time it takes for the capacitor to charge and discharge.
using CRO we can measure the rise time and fall time of the capacitor for further studies
because of charging and discharging of capacitor present in the circuit. beacause capacitor charges exponentially. akshay dabhane
The voltage across a capacitors given as a time constant t= 63% the resistor value multiply buy capacitor value. it doesn't matter if it goes more or less negative it will follow this function