if (n%2==0) sum=n/2*(n+1);
else sum=(n+1)/2*n;
Using while loop, write a program which calculates the product of digits from 1 to 5 and also show these no's vertically.
#include#include#includevoid main(){int i,j;clrscr();for(i=3;i
main() { int i,sumo=0,sume=0,oddno,evenno; for(i=1,oddno=1,evenno=2;i<=100;++i,oddno=oddno+2,evenno=evenno+2) { sumo=sumo + oddno; sume=sume + evenno; } printf("Sum of odd nos = %d And Sum of even nos = %d,sumo,sume); }
Use a linked-list.
/* program to calculate sum of two no.s in c*/ #include<stdio.h> #include<conio.h> void main() { int a,b,sum; clrscr(); cout("enter 2 nos"); cin("%d %d ",&a,&b); sum=a+b; cout("sum is %d",sum); getch(); }
if (*&a > *&b) *&max = *&a; else *&max = *&b;
10
void swap (int &pa, int &pb) { *pa ^= *pb; *pb ^= *pa; *pa ^= *pb; }
Using while loop, write a program which calculates the product of digits from 1 to 5 and also show these no's vertically.
How do you lose weight using super nos pump
If both Windows and Unix are using TCP/IP as their primary NOS there isn't much difference to speak of.
#include#include#includevoid main(){int i,j;clrscr();for(i=3;i
int sum (int n) { if (n<=1) return n; else return n + sum (n-1); }
main() { int i,sumo=0,sume=0,oddno,evenno; for(i=1,oddno=1,evenno=2;i<=100;++i,oddno=oddno+2,evenno=evenno+2) { sumo=sumo + oddno; sume=sume + evenno; } printf("Sum of odd nos = %d And Sum of even nos = %d,sumo,sume); }
It depends on the series.
The difference is using a NOS ( Network Operating System), A Domain uses a NOS whereas a Workgroup does not.
To see what we find.