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A cable suspension bridge is a kind of bridge hung from cables.
The hardening property's of cement are measured on a parabola, in other words it will keep getting harder for ever , However that does not mean that it will necessarily be stronger for the job its required to do. e.g glass is very hard but its not strong enough to make a reasonable trampoline.
Trajectory is the path a projectile follows Parabola is the shape of this path
i think that the range and the domain of a parabola is the coordinates of the vertex
Ignoring air resistance, it would be a parabola.
The coordinates will be at the point of the turn the parabola which is its vertex.
It is the parabola such that the coordinates of each point on it satisfies the given equation.
The graph (on Cartesian coordinates) of a quadratic equation is a parabola.
An "ideal" projectile trajectory ... without the influence of wind or air resistance ... is a section of a parabola. That's the figure you get when the horizontal position changes at constant speed and the vertical position changes at a speed that is itself changing at a constant rate.
The path of a projectile is a parabola because the force of gravity acts perpendicular to the initial velocity, causing the projectile to follow a curved trajectory. This curved path results from both horizontal and vertical motion, creating a parabolic shape.
A parabolic arc trajectory is the curved path that an object follows when thrown or launched into the air, under the influence of gravity. This type of trajectory is characterized by a symmetric shape resembling a parabola, with the object reaching its highest point midway through its flight path. Projectile motion, such as that of a thrown ball or a launched rocket, often follows a parabolic arc trajectory.
An "ideal" projectile trajectory ... without the influence of wind or air resistance ... is a section of a parabola. That's the figure you get when the horizontal position changes at constant speed and the vertical position changes at a speed that is itself changing at a constant rate.
Use the equation: (Y-k)^2 = 4a(X-h)
We will be able to identify the answer if we have the equation. We can only check on the coordinates from the given vertex.