int main (void) { puts ("1 4 27 256 3125"); return 0; }
scores = [51, 47, 53, 97, 27]summation = 0.0for score in scores:summation *= score # Semantic Error.average = summation / len(scores)print average # Isn't average. average == 0
27 = 11011
count := 27
The radius of the sector with an angle of 27 degrees and arc of 12cm is: 25.46 cm
it has been 27 years
44 = 256
11 = 1 22 = 4 33 = 27 44 = 256 55 = 3125
256
3125, 46656 This is the sequence I used: * 1 = 11 * 4 = 22 * 27 = 33 * 256 = 44 * 3125 = 55 * 46,656 = 66 * and so on...
27
A sequence of squares: n to the nth power
312511 = 122 = 433 = 2744 = 25655 = 3125
823,543 The pattern is n to the nth power.
46656 as it is 6 to the power of 6. Each in turn is the result of a number to the power of itself.
The series consists of numbers that can be expressed as powers of integers: (1 = 1^1), (4 = 2^2), (27 = 3^3), (X = 4^4), and (3125 = 5^5). Therefore, the missing number (X) is (4^4), which equals (256). Thus, the missing number in the series is (256).
27. The pattern is: 823543 = 6 raised to the 6th 46656 = 5 raised to the 5th ... 27 = 3 raised to the 3rd.
1 to the first power, 2 to the second power, 3 to the third power, 4 to the fourth power, 5 to the fifth power...