Assuming the question is about simple reactive control gear, e.g. a choke or inductor in series with the discharge lamp, then the following answer applies.
In an ideal situation, an ideal inductor, that is an inductor exhibiting pure inductance by virtue of its construction and the use of wire with no resistance, then the losses would be zero and the power consumed by the circuit would be V.I.Cos Phi, where Phi is the phase angle between the voltage and current.
In the real world electronic components are rarely ever perfect, and although a component may be called an inductor or choke, it will possess some parasitic resistance and possibly some stray capacitance too. The main source of the parasitic resistance is due to the resistance of the wire used to wind it, the diameter and length of the wire required to obtain a particular inductance and current rating and any eddy-current losses in an iron core if one is used. In the case of street lighting control gear designed to function at 50 or 60Hz, laminated iron cores are almost always used to obtain the relatively large inductances required. (At 240v R.M.S., 50Hz approximately 1 Henry of inductance is required to regulate a 20 Watt discharge lamp and 100mH for 200Watt lamp and 10mH for a 2Kw lamp, particular lamp types such as fluorescent, high pressure sodium or metal halide of the same power rating requiring slightly differing inductance values dependent on their discharge voltages at their specified operating currents.) The laminated iron cores are often constructed with an air gap to control the current value at which the core saturates.
In a real choke power is wasted in I squared R losses in the parasitic resistance of the wire, which appears as a low value, (hundreds of ohms for low current, high inductance chokes down to a an ohm or less for high current low inductance chokes used for large H.I.D. lamps) in series with the actual reactive inductance obtained by the number of turns, thickness of the wire and the nature of the core. Eddy current losses appear as a parallel resistance across the series combination of the actual inductance and resistance of the wire. Both of these resistive components add a small in-phase current to the large lagging current of the inductive component. (An ideal inductor exhibits a pure quadrature lagging current.) The series resistive component due to the wire is easy to measure and can simply be measured with a multi-meter on the appropriate resistance range for relatively high inductance chokes used with lamps up to about 400w rating. A four wire milli-ohm meter may be needed to measure the lower resistances of "larger" , lower inductance chokes with fewer turns of thicker wire, used with lamps rated above 400w.
Simply measuring the operating current, squaring it and multiplying this by the previously measured resistance will give the loss in the choke due to its wire resistance, but this will not include any eddy current losses in the core. Another method would be to connect the choke directly across a low source impedance A.C. voltage of the intended operating frequency. Generally most series regulating discharge lamp chokes can be connected directly across the supply voltage they are intended to be used from, (lamp shorted out), although some may saturate and in this case the voltage would need to be reduced. Under these conditions one could use a low value shunt or a suitably terminated current transformer in series with the choke under test to obtain the current waveform on an oscilloscope. The voltage waveform across the choke could also be displayed on the second channel of the oscilloscope to give both the amplitudes and phase angle between the voltage an current. Rembering to take into account the ratios of the current and voltage Transformers used and to convert the peak values to R.M.S., the in-phase component should be able to be extracted by resolving the phase ange and magnitudes from the oscilloscope into two orthogonal components. The magnitude of this in-phase component of choke current can be used to calculate all the lossy resistive components, Rt, of a real choke and thus using "Iop" squared "Rt" to get the trus losses. ("Iop", being the operating current through the choke when used with a fully run-up lamp in series.)
Some notes, low inductance, high current chokes wound on large cores with few turns of thick wire and used for H.I.D. lamps with power ratings of aroud 1Kw or more are a lot less lossy than high inductance, low current chokes used for small fluorescent tubes which are wound with many thousands of turns of fine wire with high resistance. High frequency control gear, such as that used in electronic compact fluorescent lamps. operating at frequencies of around 45-50KHz make use of the fact that inductive reactence = 2pifL, and by increasing the frequency, f, the inductance, L, can be reduced by an inverse amount and since the inductance, L, is roughly proportional to the number of turns, these can be reduced requiring a lot less wire and thus possessing a lot less resistance and thus are a lot less lossy. The losses in the rectifier and oscillator used to raise the frequency are more than compensated for by the large increase in inductance.
Measuring omic "I squared R" losses in control gear such as leak transformers and "constant wattage", CWA gear is more demanding but not impossible.
we can improve the bernoulli equation by adding the head losses at the final flow state and also we account the major (friction loss and viscus loss) losses and Minor losses (pipe bend , pipe contraction , pipe inlet and outlet, pipe fittings , valves etc)... If we account those losses and added to the head losses then the Bernoulli's equation gives the very accurate value....
Constant losses Those losses in a d.c. generator which remain constant at all loads are known as constant losses. The constant losses in a d.c. generator are: (a) iron losses (b) mechanical losses (c) shunt field losses
There are no applications for losses, that's why they are called 'losses'!
What fittings are installed and type of valves and height as friction losses have a lot to do with the calculations. Also the piping material and lenght have to be taken into consideration.
Just like a transformer, the core losses are a combination of eddy current losses and hysteresis losses.
One has to specify the size and therefore the watt usage of each type or the light output desired to compare them. Fluorescent tube lights range from 5 to 80 watts including losses in the ballast. Compact fluorescent bulbs range from 7 to over 30 watts in usage with the included ballast. LED's don't have nearly the same light output each, so you need a bunch of them to match output, but if matched use lower wattage because of low heat loss. Once you define the wattage, the total power is in watt-hours or kilowatt hours or some other conversion value.
Not much. It depends on the unit and the design. Some only use the wattage of the bulb (plus any ballast losses), and only use more in spikes when it is actively killing bugs. Others use a step-up transformer to power the killing grid, and the transformer adds to the voltage losses. So expect anything from 30 to 200 watts plus momentary spikes. You would have to consult the label and specifications for your exact unit for more details.
Friction losses through pipe and fittings and overcoming head pressure
It depends on the type of double fluorescent fixture and the tubes you use in it. If you use regular T-12 tubes, you would use 80 watts plus whatever losses you get from the ballast (up to 20 watts). If you use energy saver T-12 tubes, you would use 68 watts plus the losses from the ballast. If you use a T-8 fixture, you would use 64 watts plus whatever losses from the electronic ballast which are next to nothing in comparison to a magnetic T-12 ballast.
we can improve the bernoulli equation by adding the head losses at the final flow state and also we account the major (friction loss and viscus loss) losses and Minor losses (pipe bend , pipe contraction , pipe inlet and outlet, pipe fittings , valves etc)... If we account those losses and added to the head losses then the Bernoulli's equation gives the very accurate value....
Yes as the short radius fittings offer greater friction losses
Hot air balloons DON'T need any ballast. However gas balloons which get their lift from lighter-than-air gases, typically helium or hydrogen, do need ballast. The ballast allows the pilot to control the altitude at which the balloon flies. To gain altitude the pilot releases some ballast or vents out some gas to descend. During flight some gas will be lost through natural losses through the material of the gas envelope and the pilot counters the loss of lift by releasing ballast to maintain the altitude he wants. On long distance flights the variation between night and day time temperatures affects the amount of lift the gas exerts of the balloon. This requires further adjustment of gas venting or release of ballast to maintain the desired altitude.
The major losses within a pipe are those that occur through out the lenght of the pipe, they are caused by the interaction of the water particles and the inner surface of the pipe as water flows through it. Now minor losses are those that occur due to fitting and connections in a pipe sytem, such as 90 degree bends or turns, or valves, etc. These cause minor losses. Major losses are more significant than minor losses.
stray losses,armature copper losses,iron losses(Hysteresis and eddy current losses),mechanical losses(friction and windage losses)
Constant losses Those losses in a d.c. generator which remain constant at all loads are known as constant losses. The constant losses in a d.c. generator are: (a) iron losses (b) mechanical losses (c) shunt field losses
There are no applications for losses, that's why they are called 'losses'!
Basically two types: 1. Copper losses:- when the transformer is loaded, current flows in primary and secondary winding, there is loss of electrical energy due to the resistance of the primary winding, and secondary winding and they are called variable losses. These losses depend upon the loading conditions of the transformers. Therefore, these losses are also called as variable losses. 2. Iron losses or core losses:-The losses that occur in the core are known as core losses or iron losses. Two types of iron losses are: > eddy current loss > Hysteresis loss.