0
The big power Formulas: Formula 1 - Electrical (electric) power equation: Power P = I × V = R × I2 = V2 ⁄ R
where power P is in watts, voltage V is in volts and current I is in amperes (DC).
If there is AC, look also at the power factor PF = cos φ and φ = power factor angle
(phase angle) between voltage and amperage. Formula 2 - Mechanical (mechanic) power equation: Power P = E ⁄ t = W ⁄ t
where power P is in watts, energy E is in joules, and time t is in seconds. 1 W = 1 J/s Scroll down to related links and look at "Formulas and calculations - Electricity and Electric Charge".
What else can I help you with?
Five series resistors each dissipate 50 mW of power What is the total power?
AS:total power = P1 + P2 + P3 + .......so,total power = 5(50mW)= 0.25Wtotal power dissipated by the five resistors is 0.25W.
Is power directly proportional to resistance?
No, power is not directly proportional to resistance. The power dissipated in a circuit is given by P = I^2 * R, where I is the current flowing through the circuit and R is the resistance. This means that power is proportional to the square of the current but linearly proportional to resistance.
What is the relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit, as represented by the equation Pi2r?
The relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit is represented by the equation Pi2r. This equation shows that power dissipation is directly proportional to the square of the current and the resistance in the circuit.
What is the relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit, as represented by the equation P i2r?
The relationship between power dissipation (P), current (i), and resistance (r) in an electrical circuit is represented by the equation P i2r. This equation shows that power dissipation is directly proportional to the square of the current and the resistance in the circuit.
How is the energy dissipated by the resistor in an RC circuit calculated?
The energy dissipated by a resistor in an RC circuit is calculated using the formula: Energy 0.5 C V2, where C is the capacitance of the circuit and V is the voltage across the resistor.
What is an equation for power?
Power = (energy used)/(time to use it)Power dissipated by an electrical circuit =(voltage across the circuit) x (current through the circuit)or(resistance of the circuit) x (square of the current through the circuit)or(square of the voltage across the circuit)/(resistance of the circuit)
When you have watts in a series circuit do you add up the total or is it the reciprocal?
The power dissipated by the complete circuit, no matter whether it's a series or parallel one, is the simple sum of the power dissipated by each component of the circuit.
How do you find power in a series circuit?
Power dissipated by the entire series circuit = (voltage between its ends)2 / (sum of resistances of each component in the circuit). Power dissipated by one individual component in the series circuit = (current through the series circuit)2 x (resistance of the individual component).
Determine the power dissipated if the voltage supplied to a circuit is 12V and the current measured is 3A?
The power dissipated by a circuit with a voltage of 12V and a current of 3A is 36W. Watts is Volts times Amps.
What equation represents power?
Power = (energy dissipated or moved) / (time to move or dissipate it)
In a parallel circuit does the power of each branch add up?
Yes, the total power dissipated through the circuit is equal to the sum of the power of each branch in a parallel circuit.
How is a parallel circuit the same as a series circuit?
In both cases, the power dissipated is measured by multiplying the voltage across the circuit by the current through the circuit.
Is a series circuit the same as a parallel circuit?
In both cases, the power dissipated is measured by multiplying the voltage across the circuit by the current through the circuit.
A series circuit has 100mA flowing through a 1.5kohm load What is the power dissipated by the load?
A series circuit has 100mA flowing through a 1.5kohm load. The power dissipated by the load is equivalent to 15 Watt. This is based on the formula, power is equals to square current times load.
Five series resistors each dissipate 50 mW of power What is the total power?
AS:total power = P1 + P2 + P3 + .......so,total power = 5(50mW)= 0.25Wtotal power dissipated by the five resistors is 0.25W.
What happens to the power used in a circuit?
Usually dissipated as heat. Can be converted into light, motion, sound, etc.
What is the Power dissipated allowed by a circuit breaker with 208 volts and 5 amps?
1,040 watts or 1.04 KW.
