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For lamps in parallel, it's straightforward, as you only need to add the individual power ratings to find the total power rating and multiply this value for the time over which they operate, to determine the energy dissipation.

For lamps in parallel, it's far more complicated. Lamps in parallel are not subject to their rated voltages and, so, cannot operate at their rated powers. In fact, the lamp with the lowest power rating will actually burn the brightest! Trying to calculate what is going on is further complicated by the fact that there is significant difference in the resistance of a lamp when it is operating at its operating temperature and when it is cold, and you cannot determine these resistances theoretically. So, while you can determine the answer to your question experimentally -by measuring the current and voltage- it is not practical to calculate the answer you are looking for.

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12y ago

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