In C a character already is its ASCII value:
char c= 'A';
printf ("%c is %d (0x%x hexa)\n", c, c, c);
77
ASCII character array (including null-terminator): {'N','e','t','w','o','r','k','\0'} ASCII character codes (decimal): {78,101,116,119,111,114,107,0} ASCII character codes (octal): {4,7,1,4,5,3,5,0,7,3,5,5,7,3,4,4,6,5,4,0,0} ASCII character codes (hexadecimal): {4E,65,74,77,6F,72,6B,00} ASCII character codes (binary): {01001110,01100101,01110100,01110111,01101111,01110010,01101011,00000000} When treated as a 64-bit value, the ASCII-encoded word "Network" has the decimal value 5,649,049,363,925,854,976.
There is no ASCII value of :-) ASCII encodes only single characters, assigning a numerical 0-127 value to each character. However, if you want the ASCII encoding of a smiley, here's some samples (using Hex values): :-) 0x3A2D29 :) 0x3A29
acii value of 1 is 49 for a complete list check out: http://www.killersites.com/webDesignersHandbook/ascii_page2.htm
If the character's ASCII value is in the range of the digit characters, then it is a numeric. In ASCII, the range of digits is from '0' to '9' (48 to 57 decimal). Note that character constants such as '0' will implicitly convert to the constant integer 48 (the ASCII code for the character) so there is no need to remember the actual value; the compiler can determine this for us. The following function shows how one might test a character to see if it is a digit or not: bool is_digit (const char c) { return (c>='0' && c<='9'); } The function will return true if the given character is a digit, otherwise it will return false.
\ is the character for 92 in ASCII.
1 is an integral integer type with the numeric value 1. '1' is an integral character type with the numeric value 49. That is, ASCII character 49 returns the symbol '1'. To convert an ASCII character in the range '0' to '9' to its integral numeric value, subtract character '0' from the character. ASCII character '0' has the numeric value 48, thus '1' - '0' = 49 - 48 = 1. To convert a numeric value in the range 0 to 9 to its ASCII character equivalent, add character '0' to the value. Thus 1 + '0' = 1 + 48 = 49 = '1'.
77
ASCII character array (including null-terminator): {'N','e','t','w','o','r','k','\0'} ASCII character codes (decimal): {78,101,116,119,111,114,107,0} ASCII character codes (octal): {4,7,1,4,5,3,5,0,7,3,5,5,7,3,4,4,6,5,4,0,0} ASCII character codes (hexadecimal): {4E,65,74,77,6F,72,6B,00} ASCII character codes (binary): {01001110,01100101,01110100,01110111,01101111,01110010,01101011,00000000} When treated as a 64-bit value, the ASCII-encoded word "Network" has the decimal value 5,649,049,363,925,854,976.
There is no ASCII value of :-) ASCII encodes only single characters, assigning a numerical 0-127 value to each character. However, if you want the ASCII encoding of a smiley, here's some samples (using Hex values): :-) 0x3A2D29 :) 0x3A29
acii value of 1 is 49 for a complete list check out: http://www.killersites.com/webDesignersHandbook/ascii_page2.htm
No; ASCII itself is the character set in this case.
If the character's ASCII value is in the range of the digit characters, then it is a numeric. In ASCII, the range of digits is from '0' to '9' (48 to 57 decimal). Note that character constants such as '0' will implicitly convert to the constant integer 48 (the ASCII code for the character) so there is no need to remember the actual value; the compiler can determine this for us. The following function shows how one might test a character to see if it is a digit or not: bool is_digit (const char c) { return (c>='0' && c<='9'); } The function will return true if the given character is a digit, otherwise it will return false.
Ascii value of 5 is 53.
The ascii value of zero - is 48.
It is the apostrophe or single quote character ('). It has the ASCII code 0x27 (39 decimal).
The ASCII value for "C" is 67, for "c", 99.