Decibels (db) is 3 times the log based 2 of the difference in power.
To convert from db to power, divide by 3 and compute the inverse log based 2. For example, +6db is 26/3 or 22 or 4 times the power, and -9db is 2-9/3 or 2-3 or one eighth the power.
If you are attempting to compute voltage, remember that db is power difference, so you need to take the square root of the difference, because power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance.
The 'm' in dBm means the power is referenced to 1mW. So, the power in dBm equals 10 times the log of the power in mW, or P(dBm) = 10*log(P(mW)/1mW). For example, 1W = 1000mW, so 10*log(1000/1) = 30dBm.
Here you find the formula to convert voltage levels to decibels. Scroll down to related links and look at "How to calculate dB?"
In power wattage increases by two times for every three DBs of increase. A starting point is needed to do this calculation. The equation you're looking for is 10*log |P| = P in dB for example, 0 dB = 1 watt 10 dB = 10 watts for 13.936dB, 10^1.3936 = 24.75 watts.
Decibels (db) is relative power, log base 2, times 3. Increasing power from 200 watts to 400 watts is doubling power, so the decibel change is +3 db.800 watts would be +6 db, 1600 watts would be +9 db, 100 watts would be -3 db, 50 watts would be -6 db, and so on.
If you want to work in watts, convert 25dB to a scalling factor: 3dB = 2 x input 10dB = 10 x input 20dB = 100 x input ...25dB = 10 ^ (25/10) = 316.2 x input So the output is 15 micro Watts x 316.2 = (4700)/(10^6) = 4.7 milli watts If you want to work in dB, then convert 15 micro watts to dB: 10 * log |P| = dB = 10*log |15 x 10^6| = -48.2dB ***When you have very small (ie negative) dB, it is often referred to in dBm, or 1/1000 of dB ( 30 dBm = 0 dB) so the output is -18.2dBm + 25 = 6.8dBm, or -23.2dB
To convert sone to decibel, you can use the formula: Decibels (dB) = 40 log(sone) For example, if the loudness level is 4 sones, the equivalent decibel level would be 40 log(4) ≈ 60 dB.
the first convert the power in dBm to MW, the define of dBm=10 log (P MW) -10 log ( 1mw). example: let P=-2 dBm convert this to dB? answer: Pmw= inv log(-2/10)=0.630mw*1000 micw/mw=630 microw 10log(630)=28dB
How do I convert a .db file?
The 'm' in dBm means the power is referenced to 1mW. So, the power in dBm equals 10 times the log of the power in mW, or P(dBm) = 10*log(P(mW)/1mW). For example, 1W = 1000mW, so 10*log(1000/1) = 30dBm.
That depends on you. If you want, you can say 1 watt should be 0 dB.
Here you find the formula to convert voltage levels to decibels. Scroll down to related links and look at "How to calculate dB?"
Given P = 100 watts. Reference sound intensity Po = 10^−12 W. Reference sound intensity level LPo = 0 dB. Get power level LP in dB when entering sound power P in watts. Power level LP = 10×log (P / Po) dB = 10×log (100 / 10^−12) = 140 decibels (dB).
You cannot directly convert hertz (Hz) to decibels (dB) because they measure different quantities. Hz measures frequency, while dB measures the level or intensity of a sound signal. To get dB from Hz, you would need to measure the intensity or power of the sound and then calculate the corresponding dB value using a reference level.
In power wattage increases by two times for every three DBs of increase. A starting point is needed to do this calculation. The equation you're looking for is 10*log |P| = P in dB for example, 0 dB = 1 watt 10 dB = 10 watts for 13.936dB, 10^1.3936 = 24.75 watts.
Decibels (db) is relative power, log base 2, times 3. Increasing power from 200 watts to 400 watts is doubling power, so the decibel change is +3 db.800 watts would be +6 db, 1600 watts would be +9 db, 100 watts would be -3 db, 50 watts would be -6 db, and so on.
"dB" expresses a ratio between two different power levels. 15W can't be expressed in dB. It can only be expressed as some number of dB more or less than some other power. If the reference level is 1 watt, then 15W is written as " +17 dBW ". That means " 17 dB more power than 1 watt ". In most of electronics and telecommunications, the reference level is usually 1 milliwatt. Using that common reference level, 15W is written as " +47 dBm ". That means " 47 dB more power than 1 milliwatt ". ========================================================= The question starts from 15 watts. Using 1 watt as the reference level ... (15 watts) divided by (1 watt) = 15. 10 log(15) = +11.76 dBW (11.76 dB more power than 1 watt) Using 1 milliwatt as the reference level ... (15 watts) divided by (0.001 watt) = 15,000 10log(15,000) = +41.76 dBm (41.76 dB more power than 1 milliwatt)
dB = 10 log(power-2/power-1) = 10 log(80) = 19.03 dB