To find the length of the string we use length method. The length property returns the length of a string (number of characters we use).The length of an empty string is 0.
For example:
function myFunction() {
var str = "Hello World!";
var n = str.length;
Hope this hepls.
To display the number of words or sentences in a palindrome, first, you need to check if the input string reads the same forwards and backwards. Then, you can split the string into words using a space or punctuation as a delimiter. Finally, count the number of words (or sentences, if counting full sentences) and present that count alongside the palindrome verification.
Use the following function to count the number of digits in a string. size_t count_digits (const std::string& str) { size_t count = 0; for (std::string::const_iterator it=str.begin(); it!=str.end(); ++it) { const char& c = *it; if (c>='0' && c<='9'); ++count; } return count; }
public int getStringLength(String val) { return val.length(); } There is an inbuilt functionality in strings that counts the number of alphabets in a string called length()
Console.WriteLine("Please input a string:"); string str = Console.ReadLine(); Console.WriteLine("Number of characters: " + str.Length);
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char string[50]; int flag,count=o; clrscr(); printf("The grammar is: S->aS, S->Sb, S->ab\n"); printf("Enter the string to be checked:\n"); gets(string); if(string[0]=='a') { flag=0; for(count=1;string[count-1]!='\0';count++) { if(string[count=='b']) { flag=1; continue; } else if((flag==1)&&(string[count]=='a')) { printf("The string does not belong to the specified grammar"); break; } else if(string[count=='a']) continue; else if(flag==1)&&(string[count]='\0')) { printf("The string accepted"); break; } else { printf("String not accepted"); } getch():
To display the number of words or sentences in a palindrome, first, you need to check if the input string reads the same forwards and backwards. Then, you can split the string into words using a space or punctuation as a delimiter. Finally, count the number of words (or sentences, if counting full sentences) and present that count alongside the palindrome verification.
To count the number of 'a's in a string, you can use the count() method in Python. For example, if you have a string my_string, you can get the count of 'a's by using my_string.count('a'). This will return the total number of occurrences of the letter 'a' in the string. Finally, you can print the result using the print() function.
use Microsoft word
Use the following function to count the number of digits in a string. size_t count_digits (const std::string& str) { size_t count = 0; for (std::string::const_iterator it=str.begin(); it!=str.end(); ++it) { const char& c = *it; if (c>='0' && c<='9'); ++count; } return count; }
Assuming you want to count the number of characters in a String, you just need to call the length() method on the object. For example: String foo = "This is a string"; System.out.println(foo.length()); The above code would result in the number 16 being printed out.
public int getStringLength(String val) { return val.length(); } There is an inbuilt functionality in strings that counts the number of alphabets in a string called length()
Console.WriteLine("Please input a string:"); string str = Console.ReadLine(); Console.WriteLine("Number of characters: " + str.Length);
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char string[50]; int flag,count=o; clrscr(); printf("The grammar is: S->aS, S->Sb, S->ab\n"); printf("Enter the string to be checked:\n"); gets(string); if(string[0]=='a') { flag=0; for(count=1;string[count-1]!='\0';count++) { if(string[count=='b']) { flag=1; continue; } else if((flag==1)&&(string[count]=='a')) { printf("The string does not belong to the specified grammar"); break; } else if(string[count=='a']) continue; else if(flag==1)&&(string[count]='\0')) { printf("The string accepted"); break; } else { printf("String not accepted"); } getch():
class Count { public static void main(String args[]) { int i,c=0; int n=args.length; System.out.println("length is"+n); for(i=0;i<args.length;i++) { System.out.println(args[i]); c++; } System.out.println("number of words="+c); } }
public class count { public static void main(String[] args) { String string = "1 2 3 4"; char[] array = string.toCharArray(); System.out.println("Number of characters in string: " + string.length()); System.out.println("Number of characters in array: " + array.length); } } Output: Number of characters in string: 7 Number of characters in array: 7 So yes, spaces are taken as single characters in a string.
#include<iostream> #include<string> using namespace std; int main() { int count=0; string b; string a[6]={"technical","school","technical","hawler","school","technical"}; for(int i=0;i<6;i++) { b=a[i]; for(int j=i;j<6;j++) { if(a[j]==b) count++; } cout<<a[i]<<" "<<count<<endl; count=0; } return 0; }
substr(string, position [, count]) It extract substring starting from start and going for count characters. If count is not specified, the string is clipped from the start till the end