#include #include void main() { char string[50]; int vowel=0,consonant=0; cout<<"Enter the string"; cin.getline(string,50); for(int i=0;string[i]!='\0';i++) { switch (string[i]) { case 'a': case 'A': case 'e': case 'E': case 'i': case 'I': case 'o': case 'O': case 'u': case 'U':vowel++; continue; } if (string[i]!=' ') consonant++; } cout<<"No of vowels="<<<"\nNo of consonants="<
#include<iostream> #include<fstream> #include<string> int main() { size_t count=0; std::string vowels ("aeiouAEIOU"); std::ifstream ifs; ifs.open ("test.txt", std::ios::in); if (ifs.bad()) { ifs.close(); std::cerr << "Invalid input file.\n" << std::endl; return; } while (!ifs.eof()) { char c = ifs.get(); if ((c>='a' && c<='z') (c>='A' && c<='Z')) if (vowels.find (c) != vowels.npos) ++count; } ifs.close(); std::cout << "The file has " << count << " non-vowels.\n" << std::endl; }
That's easy to do!This script will get the POST data from an HTML form and check if it is a vowel.
You need to scan through the string and keep track of the vowelsoccurring. Here is a sample program:#include#includeint countVowels(char[] s){int count = 0, i;for( i=0; char[i] != '\0'; i++){switch(char[i]){case 'a':case 'e':case 'i':case 'u':case 'o': count++;break;}}return count;}int main(){char str[256];printf("Enter the string:\t");scanf("%s", str);printf("The number of vowels in the string are :%d\n", countVowels(str));return 0;}
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char string[50]; int flag,count=o; clrscr(); printf("The grammar is: S->aS, S->Sb, S->ab\n"); printf("Enter the string to be checked:\n"); gets(string); if(string[0]=='a') { flag=0; for(count=1;string[count-1]!='\0';count++) { if(string[count=='b']) { flag=1; continue; } else if((flag==1)&&(string[count]=='a')) { printf("The string does not belong to the specified grammar"); break; } else if(string[count=='a']) continue; else if(flag==1)&&(string[count]='\0')) { printf("The string accepted"); break; } else { printf("String not accepted"); } getch():
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build an array of vowels then do a foreach on the array and then explode the string on the array value and the answer is -1 of the result
$vowel_arr=array('a','e','i','o','u'); $string="This is my sentence"; $len=strlen($string); $vowel_cnt=0; for($i=0;$i<$len;$i++) { if(in_array($string[$i],$vowel_arr)) $vowel_cnt++; else continue; } echo "Total Vowel count is: ".$vowel_cnt;
#include<iostream> #include<fstream> #include<string> int main() { size_t count=0; std::string vowels ("aeiouAEIOU"); std::ifstream ifs; ifs.open ("test.txt", std::ios::in); if (ifs.bad()) { ifs.close(); std::cerr << "Invalid input file.\n" << std::endl; return; } while (!ifs.eof()) { char c = ifs.get(); if ((c>='a' && c<='z') (c>='A' && c<='Z')) if (vowels.find (c) != vowels.npos) ++count; } ifs.close(); std::cout << "The file has " << count << " non-vowels.\n" << std::endl; }
That's easy to do!This script will get the POST data from an HTML form and check if it is a vowel.
You need to scan through the string and keep track of the vowelsoccurring. Here is a sample program:#include#includeint countVowels(char[] s){int count = 0, i;for( i=0; char[i] != '\0'; i++){switch(char[i]){case 'a':case 'e':case 'i':case 'u':case 'o': count++;break;}}return count;}int main(){char str[256];printf("Enter the string:\t");scanf("%s", str);printf("The number of vowels in the string are :%d\n", countVowels(str));return 0;}
suppose we have a string String s = "hello how are you..."; char arr[] = s.toCharArray(); for(i = 0; i < arr.length; i++) { if(arr[i] 'u') System.out.println(arr[i]); } that is it .I hope it works.If there is a better process let me know at :- "hello2.abhishek.pal@gmail.com"...
Read the characters one at a time, and write an "if" for each of the cases. In each case, if the condition is fulfilled, increment the corresponding counter variable.
#include<stdio.h> #include<conio.h> #include<string.h> void main() { char string[50]; int flag,count=o; clrscr(); printf("The grammar is: S->aS, S->Sb, S->ab\n"); printf("Enter the string to be checked:\n"); gets(string); if(string[0]=='a') { flag=0; for(count=1;string[count-1]!='\0';count++) { if(string[count=='b']) { flag=1; continue; } else if((flag==1)&&(string[count]=='a')) { printf("The string does not belong to the specified grammar"); break; } else if(string[count=='a']) continue; else if(flag==1)&&(string[count]='\0')) { printf("The string accepted"); break; } else { printf("String not accepted"); } getch():
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No, "photosynthesis" contains other vowels already. The only time when "y" would be considered a vowel is when there are no other vowels in the word.
There is no specific collective noun for the noun vowels, in which case a noun suitable for the situation can be use, for example a group of vowels, a string of vowels, a bunch of vowels, etc.
substr(string, position [, count]) It extract substring starting from start and going for count characters. If count is not specified, the string is clipped from the start till the end