To build a 64 to 1 multiplexer using cascaded 8 to 1 multiplexer, use nine 8 to 1's. Connect the first 8 to each of the 64 inputs, then connect the ninth to the outputs of the first eight. Connect the three address lines of the eight together to form 3 of the address lines. Connect the three address lines of the ninth to form the other three, for a total of 6 address lines selecting 1 of 64 inputs.
This is a lot of logic. Fan-in and fan-out may be considerations. If you are trying to scan 64 switches, there may be a better way using an 8-bit output connected to a switch matrix (with diodes if you need more than one at a time close-able) and then connected to an 8-bit input. Even better, consider the 8279 keyboard/display controller.
Personally describing VHDL code for multiplexer can be quite difficult without prior knowledge. It takes many VHDLs to be a multiplexer.
MUX(A, B, S) = A*S + B*S' NOT(A) = MUX(0, 1, A) = 0*A + 1*A' = A' From http://noyesno.net/
A byte always contains 8 bit of information(A7, A6 ....A0) . In case you want to use only 4 bits (16 combination) of data then 2 such information can be stored/transmitted through 1 byte, so to select weather your useful data is A0, A1, A2, A3 or A4, A5, A6, A7 a nibble MUX can be used.For detailed help reply me at ishank4043@gmail.com
by using 4 NCL gates we can design or implement a half adder.gates used in half adder are TH12[1 GATE],TH22[1 GATE] and TH24COMP0 [2 GATES].this NCL have a concept of DUAL-RAIL.output we get for this are S0,S1,Cout0,Cout1.
A 32 binary number is a number stored by a computer in 32 bits. it can represent: 1) An unsigned number in the range 0 to 4,294,967,295 2) A signed number in the range -2,147,483,648 to 2,147,483,647 3) A single precision IEEE floating point number with 1 sign bit, 8 exponent bits and 23 mantissa bits give an accuracy of about 7.2 decimal digits and a range of ± 10^-38 to 10^38
help
Personally describing VHDL code for multiplexer can be quite difficult without prior knowledge. It takes many VHDLs to be a multiplexer.
using 8:1 mux....
Use the multiplexer to choose the correct output based on the inputs (use the truth table).
MUX(A, B, S) = A*S + B*S' NOT(A) = MUX(0, 1, A) = 0*A + 1*A' = A' From http://noyesno.net/
It is the enable line. Used to enable the multiplexer to function. For low enable multiplexers, strobe is set to 0 to enable the multiplexer whereas in high enable multiplexers, it is set 1 to enable the multiplexer.
Advantages are 1: it reduces number of wires. 2:it reduces circuit complexity and cost. 3:it simplifies logic design. 4:we can implement many combinational circuits using MUX. 5:it does not need kmaps and simplification.
You don't need two 4-to-1 multiplexers. You only need one 4-to-1 multiplexer, and something that functions as a 2-to-1, like a single 2-input OR gate with one input grounded.
Checkmate - 1960 Death by Design 1-32 was released on: USA: 20 May 1961
20 address line available in 16 to 1 multiplexer 16 for input lines and 4 will be selection lines.
Yes. Any basic gate's Boolean expression can be implemented using a 2:1 multiplexer and hence any combinational circuit can be implemented using only multiplexers.
f = ~s.a + s.b , thus is the function for a multiplexer. let a not gate with input x and output y. set a = 1 and b =0 to get a not gate. y = ~x.1 + x.0