To build a 64 to 1 multiplexer using cascaded 8 to 1 multiplexer, use nine 8 to 1's. Connect the first 8 to each of the 64 inputs, then connect the ninth to the outputs of the first eight. Connect the three address lines of the eight together to form 3 of the address lines. Connect the three address lines of the ninth to form the other three, for a total of 6 address lines selecting 1 of 64 inputs.
This is a lot of logic. Fan-in and fan-out may be considerations. If you are trying to scan 64 switches, there may be a better way using an 8-bit output connected to a switch matrix (with diodes if you need more than one at a time close-able) and then connected to an 8-bit input. Even better, consider the 8279 keyboard/display controller.
Personally describing VHDL code for multiplexer can be quite difficult without prior knowledge. It takes many VHDLs to be a multiplexer.
MUX(A, B, S) = A*S + B*S' NOT(A) = MUX(0, 1, A) = 0*A + 1*A' = A' From http://noyesno.net/
A byte always contains 8 bit of information(A7, A6 ....A0) . In case you want to use only 4 bits (16 combination) of data then 2 such information can be stored/transmitted through 1 byte, so to select weather your useful data is A0, A1, A2, A3 or A4, A5, A6, A7 a nibble MUX can be used.For detailed help reply me at ishank4043@gmail.com
by using 4 NCL gates we can design or implement a half adder.gates used in half adder are TH12[1 GATE],TH22[1 GATE] and TH24COMP0 [2 GATES].this NCL have a concept of DUAL-RAIL.output we get for this are S0,S1,Cout0,Cout1.
A 32 binary number is a number stored by a computer in 32 bits. it can represent: 1) An unsigned number in the range 0 to 4,294,967,295 2) A signed number in the range -2,147,483,648 to 2,147,483,647 3) A single precision IEEE floating point number with 1 sign bit, 8 exponent bits and 23 mantissa bits give an accuracy of about 7.2 decimal digits and a range of ± 10^-38 to 10^38
help
Personally describing VHDL code for multiplexer can be quite difficult without prior knowledge. It takes many VHDLs to be a multiplexer.
using 8:1 mux....
Use the multiplexer to choose the correct output based on the inputs (use the truth table).
To design an 8-to-1 multiplexer using 2-to-1 multiplexers, you can cascade multiple 2-to-1 MUXes. First, use seven 2-to-1 MUXes to select between the eight input lines (let's call them I0 to I7). The first layer consists of four MUXes combining pairs of inputs, producing four outputs. In the second layer, two additional MUXes combine these four outputs into two, and finally, one last 2-to-1 MUX selects between the last two outputs, giving you a single output based on the 3-bit select lines.
MUX(A, B, S) = A*S + B*S' NOT(A) = MUX(0, 1, A) = 0*A + 1*A' = A' From http://noyesno.net/
It is the enable line. Used to enable the multiplexer to function. For low enable multiplexers, strobe is set to 0 to enable the multiplexer whereas in high enable multiplexers, it is set 1 to enable the multiplexer.
Advantages are 1: it reduces number of wires. 2:it reduces circuit complexity and cost. 3:it simplifies logic design. 4:we can implement many combinational circuits using MUX. 5:it does not need kmaps and simplification.
You don't need two 4-to-1 multiplexers. You only need one 4-to-1 multiplexer, and something that functions as a 2-to-1, like a single 2-input OR gate with one input grounded.
20 address line available in 16 to 1 multiplexer 16 for input lines and 4 will be selection lines.
Checkmate - 1960 Death by Design 1-32 was released on: USA: 20 May 1961
Yes. Any basic gate's Boolean expression can be implemented using a 2:1 multiplexer and hence any combinational circuit can be implemented using only multiplexers.