Electricity,a power supply has a positive and negative charge,this charge is used by metal,and the metal,or any electric conducter charges from the,negative charge,and the conponent goes out the,positive charge
It depends. The 2A current, did you measure that while the soldering iron was on? Or is it rated at 2A current consumption on the device itself (on the powercable or the stem of the soldering iron). Generaly speaking you can calculted the real power consumption by using P=V*I (thus 2A*24V = 48W). But do remeber that this power consumption is in the steady state, that is, after its switch on and all transient effects have died down. To be safe allow for 3A-4A switching currents that occurs at power on.
The question is moot, here's why: First of all, the replacement must supply the correct voltage. This cannot change. You always replace a 12V supply with a 12V supply. If the replacement supply has the correct amperage, it will also have the correct volt-amperes, since (by our definition) the voltage is the same. Say the old supply was 12V, 2A. This is a 24VA supply (12 X 2 = 24). The new supply also must be 12V, so which is more important, amperes, or VA? As you can see, if we make sure the new supply is 2A, it will also mean it supplies 24VA (12 X 2 = 24). If we make sure the new supply is 24 VA it will obviously supply 2A (24/12 = 2). So, assuming the voltage stays the same, matching either VA or amperes automatically means the other value is correct.
Inductance = Magnetic Flux/Current = [ML2T-2A-1]/[A] = [ML2T-2A-2] So, Dimensional Formula of Inductance = [ML2T-2A-2]
To connect a 5V DC Solid State Relay (SSR) with a 2A, 24V DC output, first connect the control input terminals of the SSR to your 5V DC control signal, ensuring proper polarity. Next, connect the load to the output terminals of the SSR, ensuring that the load is compatible with 24V DC and does not exceed 2A. Finally, provide the appropriate 24V DC power supply to the load, making sure all connections are secure and insulated.
If it were just 12V to 5V we would be talking about a simple regulator. Since we are also talking about 1A to 2A, we are talking about some kind of inverter, perhaps a pulse width modulated power converter.
No No No. If your supply can give .2A, and you need 2 Amps, your supply's not going to cut it.
Unfortunately no, if the device calls for 2000ma you will need a 2A (amp) power supply to adequately power it.
No B/c ur unit Circuitry design for 1A u can put in 2A MAX 15A may cause burn ur unit
Yes, you can use a 5V 2A power supply for a device that requires 4.5V and 1.5A, but you need to be cautious. The voltage is higher than what the device requires, which could potentially damage it. It's best to use a power supply that matches the voltage specifications of the device, or to use a voltage regulator to step down the voltage to 4.5V. The 2A rating indicates that the power supply can provide more current than needed, which is fine as the device will only draw the current it requires.
It depends. The 2A current, did you measure that while the soldering iron was on? Or is it rated at 2A current consumption on the device itself (on the powercable or the stem of the soldering iron). Generaly speaking you can calculted the real power consumption by using P=V*I (thus 2A*24V = 48W). But do remeber that this power consumption is in the steady state, that is, after its switch on and all transient effects have died down. To be safe allow for 3A-4A switching currents that occurs at power on.
The power output of a 5V/2A charger is 10 watts.
2a to the second power. If you combine the like terms, (a to the second power + a to the second power), it would be the same as 2a to the second power.
The question is moot, here's why: First of all, the replacement must supply the correct voltage. This cannot change. You always replace a 12V supply with a 12V supply. If the replacement supply has the correct amperage, it will also have the correct volt-amperes, since (by our definition) the voltage is the same. Say the old supply was 12V, 2A. This is a 24VA supply (12 X 2 = 24). The new supply also must be 12V, so which is more important, amperes, or VA? As you can see, if we make sure the new supply is 2A, it will also mean it supplies 24VA (12 X 2 = 24). If we make sure the new supply is 24 VA it will obviously supply 2A (24/12 = 2). So, assuming the voltage stays the same, matching either VA or amperes automatically means the other value is correct.
(2a + 1)(4a2 - 2a + 1)
6a to the second power minus 8ab + 2a
Probably not. The other way around would be fine: a device that only needs 750mA will work fine on a 2A power supply, but one that needs 2A will NOT work on only 750mA, which is less than half the current required.
A 5V 2A charger outputs 10 watts of power.