How do you design and implement an application that determines and prints the number of odd even and zero digits in an integer value read from the keyboard?

Answer 1

Firstly you would need to get the user input and initialize some variables (This is all done in C#):

string text = Console.ReadLine();

int numberOfEven = 0;

int numberOfOdd = 0;

int numberOfZero = 0;

int number = 0;

Then you would need to loop through the string to see for the odd and even numbers:

while(number < text.Length) // Loops through how many times there are // numbers in the string

{

if (text[number] 0) // Just like the one before, checks if it is // odd

{

numberOfOdd ++;

}

number ++;

}

And you can print off each of the integers to get how many evens, odds and zeros there are.

Answer 2

1. Create three accumulator variables for odd, even and zero and initialise them all to zero. Note that zero is an even value. If the input value is zero, jump to step 3.
2. Divide the value by 10 and take the remainder (use the modus operator) to determine the least-significant digit. If it is odd, increment the odd accumulator, otherwise increment the even accumulator and, if the even number is zero, increment the zero accumulator. Now divide the value by 10 to shift all digits one place to the right (use integer division to ignore any fraction). If the number is still greater than zero, repeat the process.
3. Finally, print the accumulators.