Your best bet would probably be to iterate through the array using a for loop and compare each value to the current low and high values (which you would store in a local variable)
for example:
for each element in array
{
if current is less than lowest_value
lowest_value = current
else if current is greater than highest_value
highest_value = current
}
1010
int findMax(int *array) { int max = array[0]; for(int i = 1; i < array.length(); i++) { if(array[i] > max) max = array[i] } return max; }
The simplest way is usually to iterate through an array using a loop and store either the index or the value of the highest number you find. For example: int findLargestIndex(int *array, int arraysize) { int largestIndex = 0; for(int i = 0; i < arraysize; i++) { if(array[i] > array[largestIndex]) largestIndex = i; } return largestIndex; }
Basically, &array[i]; That is, the memory location for an array object with index i. Or, you can do: (array + i);
program that take three decimal number as input and find the largest among them in assembly language
Find the minimum and maximum of what? An array?
java is very most important language in computer field. .net is also useful
algebra
1010
int findMax(int *array) { int max = array[0]; for(int i = 1; i < array.length(); i++) { if(array[i] > max) max = array[i] } return max; }
write an assembly language program to find sum of N numbers
In Calculus, to find the maximum and minimum value, you first take the derivative of the function then find the zeroes or the roots of it. Once you have the roots, you can just simply plug in the x value to the original function where y is the maximum or minimum value. To know if its a maximum or minimum value, simply do your number line to check. the x and y are now your max/min points/ coordinates.
One efficient way to find the median of an unsorted array of numbers is to first sort the array in either ascending or descending order, then determine the middle value as the median.
Range = Maximum value - Minimum value
Traverse the array from index 0 until you find the number. Return the index of that number.
One efficient way to find the maximum value in a sliding window of a given array is to use a data structure like a deque (double-ended queue) to store the indices of elements in the window. By iterating through the array and maintaining the maximum value within the window, you can update the deque to ensure that it only contains relevant indices. This approach allows you to find the maximum value in the sliding window with a time complexity of O(n), where n is the number of elements in the array.
You can get many example of"c programming" Reference:cprogramming-bd.com/c_page1.aspx# integer grades