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this is question related to the strength of materials rather than the hydraulics
the basic equation for the stresses in thick walled cylinders will give you the pressure at which the respective hydraulic cylinder can be operated.
for radial stress=((piri2 )/ (r02 -ri2)) * ((1 - (ro2/r2)))
where pi is the internal pressure of the cylinder
ri is the internal radius of the cylinder.
r0 is external radius of the cylinder.
r is the radius of the point you have selected on the cylinder (this is mostly ri because it is the point were high stress is felt .apparently this formula gives the value of radial stress at point selected by you that is the 'r' value)
for tangential stress=((piri2 )/ (r02 -ri2)) * ((1 + (ro2/r2)))
adding the 'tangential stress' and the 'radial stress' would give you the value of the 'axial stress' this along with some 'factor of safety' value can determine the operating pressure of the hydraulic cylinder or in this case the internal pressure of the cylinder.
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