To find the voltage drop across a relay, you can use Ohm's Law, which states that voltage (V) equals current (I) multiplied by resistance (R). In this case, the current is 0.0015 amps and the resistance is 12,000 ohms. Therefore, the voltage drop can be calculated as V = I × R = 0.0015 A × 12,000 Ω = 18 volts. Thus, the voltage drop across the relay is 18 volts.
A voltage of 240 volts is not a common three phase voltage. Single phase kva of 240 voltas and 50 amps is I x E/1000 = 240 x 50 = 12000/1000 = 12 kVa -- Assuming the 240 volts is phase to phase voltage, and this is a three phase application: KVA = V*I*sqrt (3) = 20.78KVA
To convert amps to kilovolt-amperes (kVA), you can use the formula: kVA = (Amps × Voltage) / 1000. The voltage level is essential for the calculation, as kVA is a function of both current (in amps) and voltage (in volts). For example, at a voltage of 400V, 350 amps would be approximately 140 kVA (350 × 400 / 1000). Without the voltage value, the kVA cannot be accurately determined.
Just use Ohm's Law Voltage = Current x Resistance Amps = Voltage Divided By Resistance Amps = 120 / 260
Look on the light bulb for the voltage and the power in watts. Then divide the watts by the voltage and that gives the amps. Some CFL bulbs also state the current as well as the voltage and power, which is because they can have a poor power factor.
Yes. When the voltage drops and the power requirement (watts) stays the same, the amperage goes up.
There are zero kilowatts in amps. A voltage value has to be supplied before an answer can be given. I = W/E. Amps = Watts/Volts = 12000/Volts. Alternatively, you could state the resistance, from which the amps are determined from P/R = I2.
The V stands for volts and A is amps. If for example you have a 12kVA device and are running off a voltage of 120 volts then Amps = 12000/120 = 100. You then use the calculated amps in a wire size table to get the correct size.
To convert high voltage (HV) amps to low voltage (LV) amps, you can use the formula: HV amps = LV amps x (LV voltage / HV voltage). By rearranging the formula, you can calculate LV amps by dividing HV amps by the ratio of HV voltage to LV voltage.
At what voltage? If you know the voltage then, to get the amps those kilovolt-amps contain, you simply divide the kilovolt-amps by the voltage.
At what voltage? When you know the voltage then, to get the amps those kilovolt-amps contain, you simply divide the kilovolt-amps by the voltage.
at 230v it will use 5 to 6 amps
A voltage of 240 volts is not a common three phase voltage. Single phase kva of 240 voltas and 50 amps is I x E/1000 = 240 x 50 = 12000/1000 = 12 kVa -- Assuming the 240 volts is phase to phase voltage, and this is a three phase application: KVA = V*I*sqrt (3) = 20.78KVA
Can not do it without knowing the voltage I = E/R. Amps = Voltage/Ohms.
watts = amps (times) voltage watts (divided by) voltage = amps 140 (div by) 120 = 1.66 140 (div by) 125 = 1.12
The relationship between amps and kilowatts depends on the voltage of the circuit. To calculate the amperage for a given kilowatt value, you need to know the voltage as well. The formula to convert kilowatts to amps is Amps = (kW * 1000) / Volts.
To convert kVA to amps, you need to also know the voltage. If we assume a standard voltage of 480V, then 300 kVA would be approximately 360 amps. This is calculated by dividing the kVA by the voltage and then converting to amps using the formula: Amps = (kVA * 1000) / (1.732 * Volts) where 1.732 is the square root of 3.
To determine how many amps equal 3200 watts, you need to know the voltage of the circuit. Using the formula ( \text{Amps} = \frac{\text{Watts}}{\text{Volts}} ), if the voltage is 120 volts, then ( \text{Amps} = \frac{3200}{120} \approx 26.67 ) amps. If the voltage is 240 volts, then ( \text{Amps} = \frac{3200}{240} \approx 13.33 ) amps. Thus, the number of amps depends on the voltage used.