it is
int n=123;
printf ("%d", (n/10)%10);
i want to write a simple without using pointer or array c program which will print greatest number when i give 20 number .........How far have you gotten so far?
how to print "square" using for loop
By using "str()". Example: number = 2 yourNumber = print("Your number is %s!") % (str(number))
write a program that reads a phrase and prints the number of lowercase latters in it using a function for counting? in C program
#include<stdio.h> Void main() { int a,b; printf("Enter a Number: "); // for print function as an out-put scanf("%d",&a); //for scan function as in input /* Here we can use print function once again as: */ a=a++; printf("%d",a); }
4 x 578 = 2312 8 x 754 = 6032
clean the head by using cotton.
To count the number of 'a's in a string, you can use the count() method in Python. For example, if you have a string my_string, you can get the count of 'a's by using my_string.count('a'). This will return the total number of occurrences of the letter 'a' in the string. Finally, you can print the result using the print() function.
Yes, it is possible to do that.
i want to write a simple without using pointer or array c program which will print greatest number when i give 20 number .........How far have you gotten so far?
For N = 1 to 10 Print 2 * N Next N
how to print "square" using for loop
By using "str()". Example: number = 2 yourNumber = print("Your number is %s!") % (str(number))
In QBasic, you can print even numbers using a simple loop. For example, you can use a FOR loop to iterate through a range of numbers and then check if each number is even by using the modulus operator (MOD). Here's a sample code snippet: FOR i = 1 TO 20 IF i MOD 2 = 0 THEN PRINT i NEXT i This code will print all even numbers from 1 to 20.
Use the following:awk 'END { print NR }'Awk will count the lines and print it out.
RANDOMIZE TIMER rndNumber% = INT(RND * 100) + 1 winFlag% = 0 CLS PRINT "PROGRAM: Guess the number" PRINT PRINT "I'm thinking of a number between: 1-100. You've 7 guesses..." PRINT PRINT "Guess No" FOR eachGuessNo% = 1 TO 7 PRINT eachGuessNo%; "> "; INPUT "What is my number"; guessNum% IF guessNum% = rndNumber% THEN PRINT "Yes, correct guess; you WIN!" winFlag% = 1 EXIT FOR END IF NEXT IF winFlag% = 0 THEN PRINT "No, you guessed WRONG! I the computer WIN!" PRINT "My number was: "; rndNumber% PRINT PRINT "Again, Y/N"; yesNo$ DO yesNo$ = INKEY$ LOOP UNTIL yesNo$ <> "" IF UCASE$(LEFT$(yesNo$, 1)) = "Y" THEN RUN END
Put all the numbers in order and the median is the number that is in the middle!