How do you write a menu-driven Program in java to check a perfect and palindrane number?

Answer 1

import java.io.*;
class PerfectPalindrome
{
private boolean per(int a)
{
int b=0,c=1;
for(;c<=(a/2);c++)
{
if(a%c==0)
{
b+=c;
}
}
if(a==b)
return true;
else
return false;
}
private boolean pal(int a)
{
int b=a,c=0;
for(;b>0;b/=10)
{
int d=b%10;
c=(c*10)+d;
}
if(c==a)
return true;
else
return false;
}
public static void main()throws IOException
{
BufferedReader in=new BufferedReader(new InputStreamReader(System.in));
System.out.println("1. Find a number is a perfect one or not !");
System.out.println("2. Find a number is a palindrome or not !");
System.out.print("\nEnter your Choice: ");
int a=Integer.parseInt(in.readLine()),c;
System.out.print("Enter the Number: ");
c=Integer.parseInt(in.readLine());
boolean b;
PerfectPalindrome e=new PerfectPalindrome();
switch(a)
{
case 1: b=e.per(c);
if(b==true)
System.out.print("It is a Perfect Number !");
else
System.out.print("It is not a Perfect Number !");
break;
case 2: b=e.pal(c);
if(b==true)
System.out.print("It is a Palindrome Number !");
else
System.out.print("It is not a Palindrome Number !");
break;
default: System.out.print("SORRY!! Wrong Choice!");